A person has a 336.33 mL sample of gas at a pressure of 25.72 kPa. If the person increases the volume to 1.18L, what will the new pressure of the gas be in kPa?

Answer: 1s-n=1,l=0

3s-n=3,l=0

2p-n=2,l=1

4d-n=4,l=2

5f-n=5,l=3

Explanation: An electron has 4 quantum numbers .

n-principal quantum number (explains about the shell)

and has values 1,2,3....

l-angular quantum number (shape of the orbital)

and is described by shapes spherical (l=0),polar (l=1),clover leaf (l=2)

l=0(s subshell)

l=1(p subshell)

l=2(d subshell)

l=3(f subshell)

There can be no zero for the main quantum number (n). Therefore, the permitted values for n are 1, 2, 3, 4, and so forth.

Any integer between 0 and n – 1 can serve as the angular quantum number (l). For instance, if n = 3, l can be one of 0, 1, or 2.

Answer:

Explanation:

The n (Principal Quantum Number) and l (Azimuthal Quantum Number) values for the following orbitals are:

a)1s:  n=1 ,  l =0

b) 3s: n=3 ,  l =0

c)2p:  n=2 ,  l =1

d)4d:  n=4 ,  l =2

e)5f:   n=5 ,  l =3

In any orbital there are four different  quantum numbers i.e.,

•Principal Quantum Number

•Azimuthal Quantum Number

•Magnetic Quantum Number

• Spin Quantum Number

Principal Quantum Number tells about the shell and Azimuthal Quantum Number tells us about the shape of orbital.

For any orbital,

n=1,2,3,4,...

And l=0 to(n-1)

For example:

n=1 , l= 0

n=2 , l= 0,1

n=3 ,l=0,1,2

(Here 0 stands for s-orbital ,1for p-orbital, 2 for d-orbital and so on..)

So the n(Principal Quantum Number) and l(Azimuthal Quantum Number) values for the following orbitals are:

a)1s:  

n=1 (the 1 from "1s")and

l=0  (as 0 represents s-orbital)

b) 3s:

n=3 (the 3 from "3s")and

l =0 (as 0 represents s-orbital)

c)2p:

n=2 (the 2 from "2p")and

 l =1 (as 1 represents p-orbital)

d)4d:  

n=4 (the 4 from "4d")and

l =2 (as 2 represents d-orbital)

e)5f:  

n=5 (the 5 from "5f")and

 l =3 (as 3 represents f-orbital)

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19.42g of fluorine is produced upon decomposition of sodium fluoride.

The mass of a given substance is converted to moles using the molar mass of this substance in the periodic table. Moles of a given substance are then converted to moles of an unknown substance using the molar ratios from the balanced chemical formulas.

Mass ratio is defined as the percentage composition of the masses of elements in a molecule or compound. A compound always has a defined mass fraction of the corresponding element.

Mass ratio of sodium to fluorine = 1.21:1

If the mass of sodium fluoride produced is 23.5 g

Using dimensional Analysis,

(23.5g of sodium/sodium fluoride)×(1 g of Fluorine/1.21 g of sodium)

= 19.42g(g of fluorine/g of sodium fluoride)

Mass of fluorine produced = 19.42g

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The formula for calculating the amount of energy or heat released is:

ΔH = C ΔT

where ΔH is heat of combustion, C is heat capacity, while ΔT is change in temperature

ΔH = 8.69 kJ / °C * (5.14°C)

ΔH = 44.67 kJ

Then we calculate the moles of CH3OH which has molar mass of 32.04 g/mol:

moles = 1.922 / 32.04 = 0.05999 mol

SO the molar heat of combustion is:

ΔHm = 44.67 kJ / 0.0599875 mol

ΔHm = 744.60 kJ / mol

Mass ratio of Tristearin that react according to the reaction : \(NaOH\) is

20 : 27

The main fat in beef is tristearin. A molecule of glycerine that has interacted with three (3) molecules of the fatty acid stearic acid is known as a triglyceride.

1 mole of Tristearin requires 3 moles of \(NaOH\) to react to give 1 mole of glycerol & 3 moles of sodium sterate.

Molar ratio of reactant Tristearin : \(NaOH\) = 1 : 3

Molar weight of Tristearin = 891.5 g/mol

=> 20 g Tristearin = \(\frac{20}{891.5} moles\)

=> \(NaOH\) required to react with \(\frac{20}{891.5}\) moles of Tristearin = \(3\times\frac{20}{891.5} moles\) = 0.0673 moles

=> Molecular weight of \(NaOH\) = 40 g/mol

=> \(NaOH\) mass required to react with 20 g Tristearin = 0.0673 × 40g = 2.7g

∴ Mass ratio of Tristearin: \(NaOH\) is 20 : 27.

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To increase the gravitational force between the balloon and the golf ball, It should be filled with lead pieces. Option D

A substance's density, which measures its mass in relation to its volume, determines how much gravitational force it produces.

Lead bits are one of the suggested materials, and they are the one that would most likely boost the gravitational force. The density of lead is much higher than that of the other listed materials.

The high density of lead will result in an increase in the gravitational pull between the balloon and the golf ball if Jamie fills the balloon with lead bits.

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(A) Possible Galvanic cells:

Li(s) | Li+ solution || H+ solution | H2(g) | Pt(s)

Half-cell reactions: Li(s) → Li+(aq) + e-; 2H+(aq) + 2e- → H2(g)

Overall reaction: 2Li(s) + 2H+(aq) → 2Li+(aq) + H2(g)

Eºcell = -3.04 V

Zn(s) | Zn2+ solution || H+ solution | H2(g) | Pt(s)

Half-cell reactions: Zn(s) → Zn2+(aq) + 2e-; 2H+(aq) + 2e- → H2(g)

Overall reaction: Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g)

Eºcell = -0.76 V

Zn(s) | Zn2+ solution || O2(g) | H2O(l) | Pt(s)

Half-cell reactions: Zn(s) → Zn2+(aq) + 2e-; O2(g) + 4H+(aq) + 4e- → 2H2O(l)

Overall reaction: Zn(s) + O2(g) + 4H+(aq) → Zn2+(aq) + 2H2O(l)

Eºcell = 1.56 V

(B) The most powerful reducing agent is the one with the lowest Eo value, indicating the greatest proclivity to lose electrons and experience reduction. Based on the Galvanic cells, Li has the most negative Eo value (-3.04 V), making it the most powerful reducing substance.

(c). we can use Faraday's laws of electrolysis to calculate the current and the amount of H₂ gas produced:

Calculate the number of electrons transferred:

From the balanced reaction, we see that 2 moles of electrons (4 e⁻) are transferred for each mole of H₂ produced.

The mass of Zn consumed in 2 hours is 50 g, which is equivalent to 50/65.38 = 0.765 moles of Zn (where 65.38 g/mol is the molar mass of Zn).

Therefore, the total number of electrons transferred is 4 x 0.765 = 3.06 moles of electrons.

Calculate the current:

Faraday's first law states that the amount of chemical change in an electrolytic cell is proportional to the amount of electricity that flows through the cell.

The proportionality constant is the Faraday constant, which is equal to 96,485 C/mol e⁻.

Therefore, the total charge (Q) required to transfer 3.06 moles of electrons is:

Q = 3.06 x 96,485 = 295,038 C

The time (t) taken for this charge to flow through the circuit is 2 hours = 7,200 seconds.

Therefore, the current (I) is:

I = Q/t = 295,038/7,200 = 40.97 A

Calculate the amount of H₂ gas produced:

From the balanced reaction, we know that 1 mole of H₂ gas is produced for every 2 moles of electrons transferred.

Therefore, the number of moles of H₂ gas produced is:

0.765 moles of Zn x (1 mole of H₂/2 moles of electrons) = 0.383 moles of H₂ gas

The molar mass of H₂ is 2 g/mol, so the mass of H₂ gas produced is:

0.383 moles of H₂ gas x 2 g/mol = 0.766 g of H₂ gas

Therefore, the Galvanic cell produces 0.766 g of H₂ gas when it consumes 50 g of Zn metal for 2 hours at a current of 40.97 A.

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ΔLatticeU = ΔLatticeH – pΔVm is the lattice energy of wurtzite.  Ionic compounds often have flat surfaces that meet at distinctive angles and are stiff, brittle, crystalline materials.

Remember that when a metal reacts with a nonmetal, often an ionic compound results from the transfer of electrons form the metal (the reductant) towards the nonmetal (the oxidant). Ionic compounds often have flat surfaces that meet at distinctive angles and are stiff, brittle, crystalline materials. They melt at rather high temperatures and are not easily distorted.   ΔLatticeU = ΔLatticeH – pΔVm is the lattice energy of wurtzite.

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Answer:

D.) solidify

Explanation:

The expression 7.0x\(10^7\) ÷ 2.0x\(10^4\) can be expressed in proper scientific notation as 3.5x10^3.

To express the division 7.0x\(10^7\) ÷ 2.0x\(10^4\) in proper scientific notation, we need to perform the division and adjust the result to the appropriate format.

Dividing the numbers, we get:

7.0x\(10^7\) ÷ 2.0x\(10^4\)= 3.5x\(10^{(7-4)\)= 3.5x\(10^3\)

The result of the division is 3.5, and we adjust the exponent by subtracting the exponent of the divisor from the exponent of the dividend (7 - 4 = 3).

Therefore, the proper scientific notation representation of the division 7.0x\(10^7\) ÷ 2.0x\(10^4\) is 3.5x\(10^3\).

Scientific notation is a way to express numbers using a coefficient (in this case, 3.5) multiplied by a power of 10 (in this case, 10^3). It allows for more concise representation of very large or very small numbers.

In this case, the division resulted in a number that is smaller than the dividend and has a positive exponent, indicating a smaller magnitude compared to the original numbers. The coefficient represents the significant digits of the result, while the power of 10 represents the scale or magnitude of the number.

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The limiting reactant of the reaction is CH₄.

The molar composition of the product stream is:

The limiting reactant is determined using the stoichiometric ratios of methane (CH₄) and oxygen (O₂) in the given feed composition.

The balanced equation is:

CH₄ + 2 O₂ ----> CO₂ + 2 H₂O

From the feed composition, we have:

CH₄: 20 mole %

O₂: 60 mole %

CO₂: 20 mole %

Assuming a total feed of 100 moles.

Moles of CH₄ in the feed = 20% of 100 moles = 20 moles

Moles of O2 in the feed = 60% of 100 moles = 60 moles

Based on the balanced equation, the stoichiometric ratio is 1:2 between CH₄ and O₂.

Since we have 20 moles of CH₄ and 60 moles of O₂, we can see that there is an excess of O₂. Therefore, the limiting reactant is CH₄.

The molar composition of the product stream:

Since CH₄ is the limiting reactant, we will determine the amount of carbon dioxide (CO₂) and water (H₂O) produced based on the 90% conversion rate of CH₄.

From the balanced equation, for every mole of CH₄ reacted, we obtain one mole of CO2 and two moles of H₂O.

Moles of CO₂ produced = 90% of 20 moles = 0.9 * 20 = 18 moles

Moles of H₂O produced = 2 * (90% of 20 moles) = 2 * (0.9 * 20) = 36 moles

Total moles of products = Moles of CO2 + Moles of H2O

Total moles of products = 18 moles + 36 moles

Total moles of products = 54 moles

Therefore;

Moles of CO₂ in the product stream = 18 moles / 54 moles * 100% = 33.33%

Moles of H₂O in the product stream = 36 moles / 54 moles * 100% = 66.67%

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Answer:

Calcium hydroxide is a white precipitate, too, and it won't dissolve if more sodium hydroxide is added to the solution. No significant precipitate will be formed between calcium ions and ammonia.

Answer:

63.33%

Explanation:

To find the percentage of sugar in the milk chocolate just divide 15 by 9.5. This will give you 0.63333 (recurring). To find the percentage, times it by 100, which will give you 63.33%.

Hope this helped :)

The percentage of sugar present in the milk would be  63.33 %.

In positional notation, significant figures refer to the digits in a number that is trustworthy and required to denote the amount of something, also known as the significant digits, precision, or resolution.

As given in the problem a 15.00 g milk chocolate bar contains 9.500 grams of sugar, and we have calculated the percentage of sugar present,

The percentage of sugar present in the milk = 9.500 ×100/15

                                                                                = 63.33 %

Thus, the percentage of sugar present in the milk would be 63.33 %.

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Answer:

Argon-40

the reason this is abundent is because this is a more common isotope

Explanation:

As the freezing point depression equation states,

ΔTf = kf.m.i ,

where kf depends on the solvent, m depends on the concentration and i depends on the particles, the only parameter that changes between the two scenarios presented is i, since it relates to the amount of particles resulted in the dissolution of the solute. While a covalent compound, such as the acetic acid, remains as one particle when it dissolves (i = 1), ionic compounds such as KF dissolves into more particles. Therefore, the i for KF is greater than 1, resulting in a bigger change in freezing temperature.

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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Answer:

Chemical digestion is a vital part of the digestive process. Without it, your body wouldn't be able to absorb nutrients from the foods you eat, also chemical digestion uses enzymes to break down food

mechanical digestion involves physical movements, such as chewing and muscle contractions,

Explanation:

Answer: 4

Explanation: because the zero doesn't count

the state of y at room temperature is gas, good luck!

Answer:

Cattle produce a lot of methane gas, primarily through enteric fermentation and fermentation of their manure. Methane is a powerful greenhouse gas that, along with nitrous oxide, carbon dioxide, and some other compounds in the atmosphere, create a blanket around our planet.

Answer:

They add methane gas through enteric fermentation and fermentation of their manure

Explanation:

Hello !

Gobar gas mainly contains methane.

It is mainly a mixture of mainly methane and carbon dioxide. Methane is a major component of biogas.

INFORMATION:

We know that:

- An intravenous solution has a concentration of glucose equal to 0.312 M

And we must find the volume of solution needed to deliver 0.078 moles of glucose to the patient

STEP BY STEP EXPLANATION:

To find it, we need to use the formula of Molarity (concentration)

Is given that,

- Molarity = 0.312 M = 0.312 mol/L

- moles of solute = 0.078 mol

Now, replacing in the formula

Then, solving for liters of solution

Finally, since we need the volu

Taking into account the reaction stoichiometry and STP conditions, the volume of nitrogen monoxide gas that is created at STP when 32.2 g of solid copper reacts with excess nitric acid is 7.5677 L.

The balanced reaction is:

3 Cu(s) + 8 HNO₃(aq) → 3 Cu(NO₃)₂ (aq) + 4 H₂O(l) + 2 NO(g)

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The STP conditions refer to the standard temperature and pressure, which values are 0 °C and 1 atmosphere and are reference values for gases. In these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

The following rule of three can be applied: if by reaction stoichiometry 190.62 grams of Cu form 2 moles of NO, 32.2 grams of Cu form how many moles of NO?

moles of NO= (32.2 grams of Cu× 2 moles of NO)÷ 190.62 grams of Cu

moles of NO= 0.3378 moles

Then, 0.3378 moles of NO are formed.

Now, you can apply the following rule of three: if by definition of STP conditions 1 mole of NO occupies a volume of 22.4 liters, 0.3378 moles occupies how much volume?

volume= (0.3378 moles× 22.4 L)÷ 1 mole

volume= 7.5677 L

Finally, the volume of NO created is 7.5677 L.

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The net ionic equation for the reaction between potassium sulfide and magnesium iodide is S2- + Mg2+ -> MgS, as the potassium and iodide ions are spectator ions and do not participate in the reaction.

To determine the net ionic equation for the reaction between potassium sulfide (K2S) and magnesium iodide (MgI2), we first need to identify the ions present in each compound and then determine the products formed when they react.

Potassium sulfide (K2S) dissociates into two potassium ions (K+) and one sulfide ion (S2-):

K2S -> 2K+ + S2-

Magnesium iodide (MgI2) dissociates into one magnesium ion (Mg2+) and two iodide ions (I-):

MgI2 -> Mg2+ + 2I-

Now, we need to determine the possible products when these ions combine. Since potassium (K+) has a +1 charge and iodide (I-) has a -1 charge, they can combine to form potassium iodide (KI):

K+ + I- -> KI

Similarly, magnesium (Mg2+) and sulfide (S2-) can combine to form magnesium sulfide (MgS):

Mg2+ + S2- -> MgS

Now, we can write the complete ionic equation by representing all the ions present before and after the reaction:

2K+ + S2- + Mg2+ + 2I- -> 2KI + MgS

To obtain the net ionic equation, we remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are the potassium ions (K+) and the iodide ions (I-).

Thus, the net ionic equation for the reaction between potassium sulfide and magnesium iodide is:

S2- + Mg2+ -> MgS

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Because there are 2 Cl on the left, we will put a coefficient 2in front of HCl on the right side to balance out the Cl. This would result in an unequal amount of H, with 6 on the right side and 7 in the left, so we have to put a coefficient of 2 in front of C6H5OH and C6H4OH on both sides to balance out the H. By doing this, we would obtain an equal amount of H on both sides. The Carbon is already balanced, and so is the Oxygen.

The balanced chemical reaction equation for the reaction between aromatic phenol and chlorine gas in the presence of FeCl3 as catalyst is as follows;

C6H6O + Cl2 -------> C6H5OCl + HCl

An aromatic compound has 4n + 2 number of pi electrons. This condition is satisfied by phenol. Hence, phenol has the stability associated with aromatic compounds.

The reaction of phenol with chlorine in the presence of a catalyst such as FeCl3 is an aromatic electrophillic substitution reaction.

This reaction yields a chlorinated phenol (one of the aromatic hydrogen atoms attached directly to a C atom is replaced with a chlorine  atom and chlorophenol is formed).

A balanced chemical reaction equation is one in which the number of atoms of each element at the reactant side and the product side are equal. This condition is satisfied for the reaction;

C6H6O + Cl2 -------> C6H5OCl + HCl

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0.49 M is the molarity of the 4.9% \(H_{2}SO_{4}\) solution.

To find the molarity of a solution, we need to calculate the number of moles of the solute (\(H_{2}SO_{4}\)) present in a given volume of the solution. Here's how to determine the molarity of a 4.9% \(H_{2}SO_{4}\)solution with a density of 0.98 g/ml:

Determine the mass of the solute: The 4.9% concentration implies that 4.9 g of \(H_{2}SO_{4}\) is present in 100 g of the solution.

Calculate the volume of the solution: Divide the mass of the solution by its density. In this case, 100 g / 0.98 g/ml = 102.04 ml.

Convert the volume of the solution to liters: Divide the volume by 1000 to convert from milliliters to liters. 102.04 ml / 1000 = 0.10204 L.

Calculate the number of moles: Multiply the mass of the solute by its molar mass. The molar mass of \(H_{2}SO_{4}\) is 98.09 g/mol. Therefore, 4.9 g / 98.09 g/mol = 0.0499 mol.

Calculate the molarity: Divide the number of moles by the volume of the solution in liters. 0.0499 mol / 0.10204 L ≈ 0.49 M.

Thus, the molarity of the 4.9% \(H_{2}SO_{4}\) solution is approximately 0.49 M.

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Comparing the stabilities of two negative charges on opposite sides of the equilibrium-arrows is one method for determining whether the reactants or products are preferred in an equilibrium. Because this side has less energy, it is preferred, whichever side has the more stable negative charge.

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Answer:

The answer is C.

Explanation:

The number of particles (atoms/molecules) in 1 mole is referred to as the Avogadro's number. The Avogadro's number = 6.022 * 10 ^ 23. Therefore, the answer is C.

Answer:

So if we need to react with 88 gm. of copper 2 then at least 3-4 liters.

Explanation:

A 2.538 g sample of iron combines with chlorine gas to form an iron chloride with a mass of 7.25 g.The empirical formula of the iron chlorine is FeCl₅.

The term empirical formula is defined as  a chemical formula that exhibits the simplest whole-number ratio of the atoms in a molecule or compound.

It is obtained from experimental data such as the masses of the elements in a compound.

Given:

Number of moles of the iron

= 2.538 g/56 g/mol

= 0.045

Number of moles of chlorine = 0.204 moles

By dividing through by the lowest ratio

we have that the mole ratio is; 1: 5

Thus, the empirical formula of the iron chlorine is FeCl₅

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