A tractor uses a force of 1000N to lift a rock while doing 20,000J of work. How far did it move the rock?
200,000m
20m
2m
200m

Explanation:

When Two Samples of Water are Mixed, what Final Temperature Results?

Go to Mixing Two Amounts of Water: Problems 1 - 10

Go to calculating the final temperature when mixing water and a piece of metal

Worksheet #2

Back to Thermochemistry Menu

Example #1: Determine the final temperature when 32.2 g of water at 14.9 °C mixes with 32.2 grams of water at 46.8 °C.

This is problem 8a from Worksheet #2.

First some discussion, then the solution. Forgive me if the points seem obvious:

1) The colder water will warm up (heat energy "flows" into it). The warmer water will cool down (heat energy "flows" out of it).

2) The whole mixture will wind up at the SAME temperature. This is very, very important.

3) The energy which "flowed" out (of the warmer water) equals the energy which "flowed" in (to the colder water)

This problem type becomes slightly harder if a phase change is involved. For this example, no phase change. What that means is that only the specific heat equation will be involved

Solution Key Number One: We start by calling the final, ending temperature 'x.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 'x.' Also, make sure you understand that the 'x' we are using IS NOT the Δt, but the FINAL temperature. This is what we are solving for.

The warmer water goes down from to 46.8 to x, so this means its Δt equals 46.8 − x. The colder water goes up in temperature, so its Δt equals x − 14.9.

That last paragraph may be a bit confusing, so let's compare it to a number line:



To compute the absolute distance, it's the larger value minus the smaller value, so 46.8 to x is 46.8 − x and the distance from x to 14.9 is x − 14.9.

These two distances on the number line represent our two Δt values:

a) the Δt of the warmer water is 46.8 minus x

b) the Δt of the cooler water is x minus 14.9

Solution Key Number Two: the energy amount going out of the warm water is equal to the energy amount going into the cool water. This means:

qlost = qgain

However:

q = (mass) (Δt) (Cp)

So:

(mass) (Δt) (Cp) = (mass) (Δt) (Cp)

With qlost on the left side and qgain on the right side.

Substituting values into the above, we then have:

(32.2) (46.8 − x)(4.184) = (32.2) (x − 14.9) (4.184)

Solve for x

Answer:

The option that best describes the relationship between frequency and wavelength of electromagnetic waves is the third option

c. The frequency increases as the wavelength decreases

Explanation:

The frequency of an electromagnetic wave, 'f', is given by the following formula;

\(Frequency, \, f = \dfrac{Wave \ Speed,v }{Wavelength, \ \lambda}\)

From the above formula, the frequency of an electromagnetic wave is inversely proportional to the wavelength, and therefore, a higher frequency, ('f', to increase), requires a lower wavelength, (λ, decreases)

The correct option is that the frequency of an electromagnetic increases as the wavelength of the wave decrease.

Alpha particles have highest mass.

Alpha particles are most ionising.

Gamma particles are the most penetrating.

Beta particles are negatively charged.

Gamma particles have the highest speed.

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The total weight of screws and nails that Henry bought to build the skate board ramp is 13/20 pounds.

To find the total weight of screws and nails, we need to add the weight of the screws and the weight of the nails.

Henry bought 1/4 pound of screws and 2/5 pounds of nails, so

Total weight = 1/4 + 2/5 pounds

Total weight = (1 x 5)/(4 x 5) + (2 x 4)/(5 x 4) pounds

Total weight = (5/20) + (8/20) pounds

Now that both fractions have the same denominator, we can add them together,

Total weight = 13/20 pounds

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--The complete question is, henry bought 1/4 pound of screws and 2/5 pounds of nails to build a skate board ramp what is the total weight of the screws and nails?--

Answer:

please let me know when you find it

Explanation:

i have the same question and cant find it

Answer:

It’s 5m/s^2

Explanation:

Option B, C, and E are correct. First principle of motion options that address the issue include Before an item may move, it must be subjected to a net force. The inertia rule is another term for the first principle of Newton's theory of motion.

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Complete question: Inertia is an object's natural tendency to remain in constant motion or at rest. An object moving through outer space, for example, will continue moving in one direction and at a constant speed due to its inertia, if no other forces act on it. Why do planets constantly change the direction in which they move?

A. Most planets do not have any inertia, so their motion constantly changes.

B. The force of gravity acts on planets and changes the direction of their motion.

C. Each planet's inertia is constantly changing from one moment to the next.

D. There are no forces acting on the planets as they move in orbits around the Sun.

t=10s (provided in the question)

u=0m/s

the initial velocity is taken as 0 as the body is starting from rest even if it is falling.

s=?

a=-g =-9.8 (acceleration due to gravitation)

Let v be final velocity.

Where 't' represents time, 's' represents distance, 'u' is initial velocity while 'g' is the acceleration due to gravity.

Now using the second equation of Newton's equations of Motion.

s=ut+1/2a\(t^{2}\)

Now putting values into the equation above:

s=(0)(10)+1/2(-9.8)x\((10)^{2}\)

s=0-1/2x9.8x100

s=-4.9x100

s=-490m

That is the distance is 490m where the negative sign represents the direction of the distance towards the earth instead of away from it.

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Answer: A.

Explanation:

Solar eclipse happens when Sun casts a shadow directly on Earth and the Moon. Option A is correct.

A solar eclipse occurs when the Sun throws a shadow directly on Earth and the Moon.

When the Sun throws a shadow directly on the Earth and the Moon, it is called a solar eclipse.

Hence,option A is correct.

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Answer:

The easiest way to do this is to realize that the time to fall is the same as the rise time (conservation of energy can easily verify this)

S = 1/2 g t^2      time to fall 2.5 m

t = (5 / 9.8)^1.2 = .714 sec         time in air

v = a t = 9.8 * .714 = 7 m/s     initial vertical speed

Check:

S = v t - 1/2 g t^2       where v is the initial vertical speed

S = 7 * .714 - 4.9 * .714^2 = 2.5 m        total vertical distance traveled

Answer:

To describe motion accurately and completely, a frame of reference is necessary. frame of reference ( or reference frame) consists of an abstract coordinate system and the set of physical reference points that uniquely fix ( locate and orient ) the coordinate system and standardize measurements within that frame.

Explanation:

The different observations occur because the two observers are in different frames of reference. A frame of reference is a set of coordinates that can be used to determine positions and velocities of objects in that frame; different frames of reference move relative to one another.

The mean free path where commercial aircraft fly (about 30,000 ft) is nearest 0.0076 mm. (A)

The mean free path is the average distance a molecule can travel before it collides with other molecules in the atmosphere. This is important for aircraft because collisions with molecules can cause drag on the aircraft and reduce its performance.

At high altitudes, there is less air density, so the mean free path increases. At 30,000 ft, the mean free path is around 0.0076 mm, which is the closest answer to the given options.

This is because the air density at this altitude is much lower than at lower altitudes, so the molecules have a longer distance to travel before they collide.

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The frequency range of electromagnetic waves of X-ray is 3 ×10¹⁶ Hz to  3 ×10¹⁹ Hz. The wavelength range of electromagnetic waves of X-ray is  0.01 nm t0 10 nm.

The electromagnetic spectrum of electromagnetic waves can be described as the range of frequencies of electromagnetic radiation and its wavelengths and photon energies. The electromagnetic spectrum have range from one Hertz to above 10²⁵ Hertz.

The wavelength of electromagnetic radiation lies in between 380 to 760 nm and is detected by the human eye and characterized as visible light.

Electromagnetic waves of each frequency band are known by different names; starting at the low frequency (long wavelength) end of the spectrum these are radio waves, microwaves, infrared (IR), visible light, UV, X-rays, and gamma rays at the high-frequency (short wavelength) end.

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Answer:

The shadow would be on your left side.

Explanation:Give brainliest if this helped :)

The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.

The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:

RC = τ, where R is the resistance and C is the capacitance of the circuit.

Rearranging the above formula, we get:R = τ / C

Where τ is the time constant and C is the capacitance of the circuit.

From the figure, the capacitance is given as 0.1 μF

.Substituting the values of τ and C in the above formula, we get:

R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)

R = 220 Ω

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Answer:

7.2 seconds

Explanation:

50=5

72=t, criss-cross, t=72 (5)/50

A vector is an example of a physical quantity that includes information about force and mass. Thisn.statement is true

In physics, a vector is a quantity that has both magnitude and direction. It represents physical quantities that require both a numerical value and a specific direction to be fully described. Force and mass are two physical quantities that can be represented as vectors. Force is a vector quantity because it has both magnitude and direction. It describes the interaction between two objects and is characterized by its magnitude (measured in units of Newtons) and the direction in which it acts. Forces can be added, subtracted, and manipulated using vector operations.

Mass, although a scalar quantity (having only magnitude), can be associated with a vector through Newton's second law of motion. According to this law, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Since acceleration is a vector quantity, it implies that the net force acting on an object is also a vector. Hence, a vector is an example of a physical quantity that can include information about force and mass.

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Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

Answer:

Explanation:

Given:

F = 300 N

p = 20 N/m²

__________

A - ?

Valid for the area A:

A = F / p

A = 300 / 20 = 15 m²

Answer:

B train!

Explanation:

A train travelled at 40 km/hr. (120/3)

B train traveled at 45 km/hr (180/4)

Answer:

Train B

Explanation:

Let's find each train's speed using the following formula.

\(s=\frac{d}{t}\)

where \(d\) is distance and \(t\) is time.

Train A

Train A travelled a distance of 120 kilometers in 3 hours.

\(s=\frac{d}{t}\\d=120 km\\t= 3hrs\)

Substitute the values into the formula and divide.

\(s=\frac{120km}{3hrs}\\\)

\(s= 40 km/hr\)

Train B

Train B travelled a distance of 180 kilometers in 4 hours.

\(s=\frac{d}{t}\\d=180 km\\t= 4hrs\)

Substitute the values into the formula and divide.

\(s=\frac{180km}{4 hrs}\\\)

\(s= 45 km/hr\)

45 kilometers per hour is greater than 40 kilometers per hour, so Train B travelled faster.

The statement is true. ions are free to move when dissolved in water.

As solids, ionic compounds won't conduct electricity. This is because ions are organized in an ionic lattice, which prevents them from moving freely within a solid. Conduction happens when an ionic substance is dissolved in solution or molten because the ionic lattice is broken, allowing the ions to move about freely. Ionic compounds do not conduct electricity when they are in the solid state because there are no free electrons and no chances for ions to form. Whenever ionic chemicals are melted or dissolved in water, an electric current is produced. The B ions migrate toward the positive electrode in an ionic solution, while the A+ ions migrate toward the negative electrode.

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Number οf phοtοns per cubic millimeter = Number οf phοtοns / (Vοlume in cubic millimetres)

Tο find the physical length οf the pulse as it travels thrοugh space, we can use the equatiοn:

Length = (Speed οf light) x (Time)

(a) First, let's cοnvert the pulse duratiοn frοm picοsecοnds (ps) tο secοnds (s):

14.0 ps = 14.0 × \(10^{(-12)} s\)

The speed οf light is apprοximately 3 × \(10^8\) m/s, but we need tο cοnvert it tο the apprοpriate units tο match the pulse duratiοn. Sο, the speed οf light in picοmeters per secοnd (pm/s) is:

3 × \(10^8\) m/s = 3 × \(10^{14\) pm/s

Nοw we can calculate the length οf the pulse:

Length = (3 × \(10^{14\) pm/s) × (14.0 ×\(10^{(-12)} s\) )

(b) Tο find the number οf phοtοns in the pulse, we can use the equatiοn:

Energy οf the pulse = Number οf phοtοns × Energy per phοtοn

Given that the energy οf the pulse is 3.00 J and the wavelength οf the laser is 694.3 nm, we can calculate the energy per phοtοn using the equatiοn:

Energy per phοtοn = (Planck's cοnstant) × (Speed οf light) / (Wavelength)

Planck's cοnstant is apprοximately 6.626 × \(10^{(-34)\) J·s.

Nοw we can calculate the energy per phοtοn:

Energy per phοtοn = (6.626 × \(10^{(-34)\) J·s) × (3 × \(10^8\) m/s) / (694.3 × \(10^{(-9)\)m)

The number οf phοtοns in the pulse can be fοund by rearranging the equatiοn:

Number οf phοtοns = Energy οf the pulse / Energy per phοtοn

(c) Tο find the number οf phοtοns per cubic millimeter, we need tο knοw the vοlume οf the beam. The vοlume οf a cylinder is given by the equatiοn:

Vοlume = π × (Radius)² × Length

The radius οf the circular crοss sectiοn is half the diameter, sο it is 0.300 cm (οr 0.003 m).

The number οf phοtοns per cubic millimeter can be calculated by dividing the number οf phοtοns by the vοlume οf the beam in cubic millimeters:

Number οf phοtοns per cubic millimetre = Number οf phοtοns / (Vοlume in cubic millimeters)

Let's calculate the results:

(a) The physical length οf the pulse:

Length = (3 × \(10^{14\) pm/s) × (14.0 × \(10^{(-12)\) s)

(b) The number οf phοtοns in the pulse:

Energy per phοtοn = (6.626 × \(10^{(-34)\) J·s) × (3 × \(10^8\) m/s) / (694.3 ×\(10^{(-9)\)m)

Number οf phοtοns = Energy οf the pulse / Energy per phοtοn

(c) The number οf phοtοns per cubic millimeter:

Vοlume = π × (0.003 m)² × Length

Number οf phοtοns per cubic millimetre = Number οf phοtοns / (Vοlume in cubic millimetres)

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Answer:

For which the reasoning of the boy is correct for small heights, but as height increases his analysis is not correct.

Explanation:

The force of gravity comes from Newton's second law with the force the universal attraction

         F = ma

         F = \(G \frac{m_1 M}{(R_e +h)^2}\)

we substitute

          \(G \frac{m_1 M}{ (R_e+ h)^2}\) = m₁ a

where Re is the radius of the Earth 6.37 106 m

          a = \(G\frac{M}{R_e^2} \ ( 1 + \frac{h}{R_e})^{-2}\)

In general, the height is much less than the radius of the earth, therefore the term ha / Re is very small and we can use a series expansion leaving only the first fears.

             (1 + x)⁻² = 1 -2x + \(\frac{2 \ 1}{2!}\)  x²

we substitute

          a = g₀ (\(1 - 2 \frac{h}{R_e}\) )

with

         g₀ = \(G \frac{M}{R_e^2}\)

let's launch the expression.

* For small height compared to the radius of the earth we can neglect the last term

          g = g₀

* For height comparable to the radius of the Earth

          g = g₀  \((1 - \frac{2h}{Re} )\)

We see that the acceleration of gravity is decreasing.

For which the reasoning of the boy is correct for small heights, but as height increases his analysis is not correct.

The student's reasoning gone wrong when the analysis is undertaken for the increasing heights, to drop the object.

The given problem is based on the concept of gravity and gravitational force. The force of gravity comes from Newton's second law with the force the universal attraction as,

F = ma

\(F=G\dfrac{mM}{(R+h)^{2}}\\\\\\ma = G\dfrac{mM}{(R+h)^{2}}\)

Here, a is the linear acceleration, m is the mass of object, M is the mass of Earth, R is the radius of Earth and h is the height from where the objects will be dropped. Then,

\(a = \dfrac{GM}{R^{2}} \times(1+h/R)^{-2}\)

In general, the height is much less than the radius of the earth, therefore the term h/ R is very small, hence can be neglected.

\(a = \dfrac{GM}{R^{2}}\\\\a=g = \dfrac{GM}{R^{2}}\)

g is the gravitational acceleration.

For small height compared to the radius of the earth we can neglect the last term as,

a = g

And for the height comparable to radius of Earth,

\(a = \dfrac{GM}{R^{2}} \times(1+h/R)^{-2}\\\\a=g \times(1+h/R)^{-2}\)

Clearly, the acceleration of gravity is decreasing, for which the reasoning of the boy is correct for small heights, but as height increases his analysis is not correct.

Thus, we can conclude that the student's reasoning gone wrong when the analysis is undertaken for the increasing heights, to drop the object.

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Answer:

Abiotic referfers to non-living and biotic factors are living or once living

Explanation:

Answer:

A. quart

B. gram

C. Meter

Explanation:

Answer:

A. meter

B. liter

C. pound

Explanation: First kid is not right at all i am

A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

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The force of friction between the surface and the object must be equal to 10 N. In order to keep an object moving at a constant speed, the force of friction must be equal to the force applied to it.

In this question, we have given that a horizontal force of 10 newtons is needed to keep an object weighing 20 newtons moving at a constant speed. We need to find the force of friction between the surface and the object. If the object is moving at a constant speed then it is said to be in equilibrium. When an object is in equilibrium then the net force acting on it will be zero. Therefore, the force of friction between the surface and the object must be equal to the force applied to it in order to move it. Mathematically, it can be represented as follows:

The force of friction = Force applied = 10 N. To move any object from its state of rest or to keep it moving, a force is required to be applied. Once the object starts moving, it can be kept moving at a constant speed if the force applied and the force of friction is balanced. The force of friction is defined as the resistance force between two objects when they come in contact with each other. There are different types of frictional forces such as static friction, kinetic friction and rolling friction. When an object is at rest, the force of static friction must be overcome to move the object. Kinetic friction comes into play when an object is already in motion and rolling friction is experienced by the objects that are rolling over the surface. In this question, we have given that a horizontal force of 10 newtons is needed to keep an object weighing 20 newtons moving at a constant speed.

We need to find the force of friction between the surface and the object. If the object is moving at a constant speed then it is said to be in equilibrium. When an object is in equilibrium then the net force acting on it will be zero. Therefore, the force of friction between the surface and the object must be equal to the force applied to it in order to move it. Mathematically, it can be represented as follows: Force of friction = Force applied = 10 N. Hence, the force of friction between the surface and the object must be equal to 10 N. The force of friction between the surface and the object must be equal to 10 N. In order to keep an object moving at a constant speed, the force of friction must be equal to the force applied to it.

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The coefficient of static friction between the object and surface, given that a force of 23.5 N is required to set the object in motion is 0.22

Coefficient of friction is defined according to the following formula:

Frictional force (F) = coefficient of friction (μ) × normal reaction (N)

Divide both sides by normal reaction (N)

Coefficient of friction (μ) = Frictional force (F) / normal reaction (N)

μ = F / N

The following data were obtained from the question:

The coefficient of static friction can be obtained as follow:

Coefficient of friction (μ) = Frictional force (F) / normal reaction (N)

μ = F / N

μ = 23.5 / 107.8

μ = 0.22

Thus, we can conclude that the coefficient of friction is 0.22

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