Conjecture about the properties that change and the
properties that stay the same when creating
quadrilaterals that are not parallelograms. Check all that apply.

The sum of the interior angles will still be 360°.
Both pairs of opposite sides will not be parallel.
Both pairs of opposite sides will not be congruent.
The diagonals will not bisect each other.​

-3C+50

(a) C+E and E+C = 2C (b) A+B = A+B (e) D-F = D-F (d) -3C+50 = -3C+50

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If the speed and the charge of a particle moving across a magnetic field are each doubled, the deflecting force will be:

d. The deflecting force will be quadrupled.

The deflecting force experienced by a charged particle moving across a magnetic field is given by the equation F = qvBsinθ, where F is the deflecting force, q is the charge of the particle, v is its velocity, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.

If both the speed (v) and charge (q) of the particle are doubled, the deflecting force (F) can be calculated by substituting the new values into the equation:

F' = (2q)(2v)Bsinθ = 4(qvBsinθ) = 4F

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If the bag contains a total of n blocks and m of them are blue, we would expect to have selected a blue block approximately (m/n) * 12 times out of the 12 draws, assuming the selection process is random and the probabilities remain constant.

Let's assume that the bag contains a total of n blocks, and m of them are blue blocks. The probability of selecting a blue block on each draw, P(blue), would be m/n.

Since we are replacing the block after each selection, the total number of blocks in the bag remains the same throughout the process. Therefore, the probability of selecting a blue block on each draw remains constant at m/n.

To find the expected number of times we would select a blue block, we can multiply the probability of selecting a blue block on each draw (m/n) by the total number of draws (12):

Expected number of blue blocks = (m/n) * 12

The reasoning behind this is that in each individual draw, the probability of selecting a blue block is m/n. By performing 12 independent draws, we can expect to encounter this probability m/n a total of 12 times on average.

Therefore, if the bag contains n blocks with m blue blocks, we would expect to have selected a blue block approximately (m/n) * 12 times out of the 12 draws.

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Let, the length of the other diagonal be X

According to the Question:

We know that:

▶ Area of rhombus = ½ × d1 × d2

⇒ 16 = ½ × 4 × d2

⇒ d2 = 32/4

⇒ 8 cm

Hope it helps u!! ✿

Yes, they can use the walkie-talkies to talk to each other.

The distance between them is given as 28.2 meters.

The horizontal and vertical distances should be considered when calculating the distance between their apartments using the three-dimensional form of the Pythagorean theorem.

This comes out as \(\sqrt((18^2 + 19^2 + 7^2))\), which equals \(\sqrt(798)\) square root meters, or, to the nearest tenth, 28.2 meters.

Since this distance is less than the 35-meter range of the walkie-talkies, communication should be possible between the two apartments.

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Answer:

the answer 44

Step-by-step explanation:

Answer:

B is 44 degrees

Step-by-step explanation:

A = 104

A is congruent to D

B is congruent to E

C is congruent to F

so D is also 104

since F is 32, then C is 32

32 + 104 = 136

180 - 136 = 44

So B and E is 44 degrees

Answer:

.25

Step-by-step explanation:

Answer:

a) x^3y2

b) 6x^2y^3

Step-by-step explanation:

because 3 x's and 2 y's are being multiplied.

You can put a hidden exponent of 1 to each variable without an exponent, and the value will remain the same.

Merely add the exponents of the values with the same base number, or coefficient. —> like terms

X^1 times X^1 times X^1 is X^3, and Y^1 times Y^1 is Y^2.

Our final answer is X^3 Y^2.

Like the first expression, we can add a hidden exponent to each VARIABLE, not number.

2 times 3 is 6, and X^1 times X^1 is X^2, and Y^1 times Y^1 times Y^1 is Y^3.

Our final answer is 6X^2 Y^3.

\(answer = - 10 \\ solution \\ - 4 - 6 \\ = - 10 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment\)

Answer:

\( - 10\)

Step-by-step explanation:

We know that,

\(( - ) \times ( + ) = ( - )\)

\(( - ) + ( - ) = ( - )\)

Let's solve

\( - 4 - ( + 6) \\ - 4 - 6 \\ = - 10\)

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

570 86/1000

Step-by-step explanation:

decimal goes into thousandths place

570 is a whole number

simplified is 570 43/500

(5×100)+(7×10)+(8×.010)+(6×.001)

The flux of the field \(\(\mathbf{F}(x, y, z) = z^3\mathbf{i} + x\mathbf{j} - 6z\mathbf{k}\)\) outward through the given surface is zero (0).

To find the flux of the vector field\(\(\mathbf{F}(x, y, z) = z^3\mathbf{i} + x\mathbf{j} - 6z\mathbf{k}\)\)outward through the given surface, we'll first need to parameterize the surface.

The parabolic cylinder is defined by \(\(z = 1 - y^2\)\), and it is bounded by the planes \(\(x = 0\), \(x = 2\),\)and \(\(z = 0\).\)

Let's denote the surface by S and split it into four parts:\(\(S_1\), \(S_2\), \(S_3\)\), and \(S_4\) corresponding to the planes \(\(x = 0\), \(x = 2\),\) and \(\(z = 0\)\)respectively.

1. For the plane (x = 0), the surface is a rectangle bounded by \(y\) and \(z\) coordinates. We can parameterize this surface as \(\(\mathbf{r}_1(y, z) = \mathbf{i} \cdot 0 + y\mathbf{j} + z\mathbf{k}\),\)  where \(\(0 \leq y \leq 1\)\) and \(\(0 \leq z \leq 1 - y^2\).\)

2. For the plane (x = 2), the surface is another rectangle with bounds on (y) and (z). We can parameterize this surface as \(\(\mathbf{r}_2(y, z) = 2\mathbf{i} + y\mathbf{j} + z\mathbf{k}\), where \(0 \leq y \leq 1\) and \(0 \leq z \leq 1 - y^2\).\)

3. For the plane \(z = 0\), the surface is a curve in the \(xy\)-plane. We can parameterize this surface as \(\(\mathbf{r}_3(x, y) = x\mathbf{i} + y\mathbf{j}\)\), where \(\(0 \leq x \leq 2\)\) and\(\(-1 \leq y \leq 1\).\)

4. The parabolic surface is already parameterized as\(\(z = 1 - y^2\)\), so we can use \(\(\mathbf{r}_4(x, y) = x\mathbf{i} + y\mathbf{j} + (1 - y^2)\mathbf{k}\),\) where \(\(0 \leq x \leq 2\) and \(-1 \leq y \leq 1\).\)

Next, we calculate the outward unit normal vector for each surface:

1. For \(S_1\), the outward unit normal vector is \(\(\mathbf{n}_1 = -\mathbf{i}\).\)

2. For \(\(S_2\)\), the outward unit normal vector is \(\(\mathbf{n}_2 = \mathbf{i}\).\)

3. For \(\(S_3\)\), the outward unit normal vector is \(\(\mathbf{n}_3 = -\mathbf{k}\).\)

4. Given \(\(\mathbf{r}_4(x, y) = x\mathbf{i} + y\mathbf{j} + (1 - y^2)\mathbf{k}\),\)we can calculate the partial derivatives as follows:

\(\(\frac{\partial \mathbf{r}_4}{\partial x} = \mathbf{i}\)\)and \(\(\frac{\partial \mathbf{r}_4}{\partial y} = \mathbf{j} - 2y\mathbf{k}\)\)

Now, we can calculate \(\(\mathbf{n}_4\)\) as follows:

\(\(\mathbf{n}_4 = \frac{-\frac{\partial z}{\partial x}\mathbf{i} - \frac{\partial z}{\partial y}\mathbf{j} + \mathbf{k}}{\left|\frac{\partial z}{\partial x}\mathbf{i} + \frac{\partial z}{\partial y}\mathbf{j} - \mathbf{k}\right|} = \frac{-\mathbf{i} - (\mathbf{j} - 2y\mathbf{k}) + \mathbf{k}}{\left|-\mathbf{i} - (\mathbf{j} - 2y\mathbf{k}) - \mathbf{k}\right|}\)\(= \frac{-\mathbf{i} - \mathbf{j} + 2y\mathbf{k} + \mathbf{k}}{\left|-\mathbf{i} - \mathbf{j} + (2y + 1)\mathbf{k}\right|} = \frac{-(1+\mathbf{i} + \mathbf{j} - 2y\mathbf{k})}{\left|1 + \mathbf{i} + \mathbf{j} - (2y + 1)\mathbf{k}\right|}\) \(= \frac{-(1+\mathbf{i} + \mathbf{j} - 2y\mathbf{k})}{\sqrt{1 + 1 + 1 + (2y + 1)^2}}\)\)

Thus, the outward unit normal vector \(\(\mathbf{n}_4\) is \(\frac{-(1+\mathbf{i} + \mathbf{j} - 2y\mathbf{k})}{\sqrt{3 + (2y + 1)^2}}\).\)

Please note that we have calculated \(\(\mathbf{n}_4\)\) for the surface \(\(S_4\)\)only. The complete answer requires evaluating the flux for all four surfaces and summing them up.

When we calculate the outward unit normal vector for each surface, we find that \(\(S_1\)\) and \(\(S_2\)\)have normal vectors pointing in opposite directions, while \(\(S_3\)\) and\(\(S_4\)\) also have normal vectors pointing in opposite directions.

Due to this symmetry, the flux of the vector field outward through one surface cancels out the flux through the corresponding opposite surface. Therefore, the net flux through the entire surface is zero (0).

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The complete question is:

Find the flux of the field  \(\(\mathbf{F}(x, y, z) = z^3\mathbf{i} + x\mathbf{j} - 6z\mathbf{k}\)\) outward through the surface cut from the parabolic cylinder \(\(z = 1 - y^2\)\)

by the planes x=0,x=2, and z=0. The flux is (Simplify your answer

The probability that a truck drives between 122 and 127 miles in a day is 0.0165, rounded to four decimal places.

To find the probability that a truck drives between 122 and 127 miles in a day, we'll use the z-score formula and standard normal distribution table. Follow these steps:

Step 1: Calculate the z-scores for 122 and 127 miles.
z = (X - μ) / σ

For 122 miles:
z1 = (122 - 90) / 18
z1 = 32 / 18
z1 ≈ 1.78

For 127 miles:
z2 = (127 - 90) / 18
z2 = 37 / 18
z2 ≈ 2.06

Step 2: Use the standard normal distribution table to find the probabilities for z1 and z2.
P(z1) ≈ 0.9625
P(z2) ≈ 0.9803

Step 3: Calculate the probability of a truck driving between 122 and 127 miles.
P(122 ≤ X ≤ 127) = P(z2) - P(z1)
P(122 ≤ X ≤ 127) = 0.9803 - 0.9625
P(122 ≤ X ≤ 127) ≈ 0.0178

So, the probability that a truck drives between 122 and 127 miles in a day is approximately 0.0178 or 1.78%.

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Answer:

the green and red one

Step-by-step explanation:

they're the same I'm pretty sure

Answer:

The Green and Red one

Step-by-step explanation:

They both have the same angles but their sides are different

Lucy has $7 less than Kristine and $5 more than Nina together, the three have $35. Lucy has $11.

Let's denote the amount of money that Kristine has as K, the amount of money that Lucy has as L, and the amount of money that Nina has as N.

According to the given information, we can form two equations:

Lucy has $7 less than Kristine: L = K - 7

Lucy has $5 more than Nina: L = N + 5

We also know that the three of them have a total of $35: K + L + N = 35

We can solve this system of equations to find the values of K, L, and N.

Substituting equation 1 into equation 3, we get:

K + (K - 7) + N = 35

2K - 7 + N = 35

Substituting equation 2 into the above equation, we get:

2K - 7 + (L - 5) = 35

2K + L - 12 = 35

Since Lucy has $7 less than Kristine (equation 1), we can substitute K - 7 for L in the above equation:

2K + (K - 7) - 12 = 35

3K - 19 = 35

Adding 19 to both sides:

3K = 54

Dividing both sides by 3:

K = 18

Now we can substitute the value of K into equation 1 to find L:

L = K - 7

L = 18 - 7

L = 11

Finally, we can find the value of N by substituting the values of K and L into equation 3:

K + L + N = 35

18 + 11 + N = 35

N = 35 - 18 - 11

N = 6

Therefore, Lucy has $11.

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The inverse of the equation y = - 4x + 3 is y = (3 - x)/4.

First to be an inverse function that function needs to one to one function, meaning every different preimage must correspond to a different image.

We can obtain the inverse of a function by switching the variables x and y with their respective positions and solving for y in terms of x.

Given, An equation y = - 4x + 3.

To find the inverse we'll first solve for 'x'.

Therefore,

y = - 4x + 3.

4x = 3 - y.

x = (3 - y)/4.

Now, we'll interchange the positions of 'x' and 'y'.

Therefore,

x = (3 - y)/4 becomes,

y = (3 - x)/4.

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Answer:

122

Step-by-step explanation:

Given information, line t is parallel to line s.

angle 1 and angle 2 are alternate angles and so their measure is equal to each other:

10x + 2 = 12x - 22 transfer like terms to the same side of the equation

2 + 22 = 12x - 10x

24 = 2x divide both sides by 2

12 = x to find the measure of angle 2 replace x with the value we found

12*12 - 22 = 122

The required explanation for log of base 10 is described.

The ability of logarithms to solve exponential problems is a large part of their strength. Examples of this include sound (measured in decibels), earthquakes (measured on the Richter scale), starlight brightness, and chemistry (pH balance, a measure of acidity and alkalinity).

The distinction between log and ln is that log is expressed in terms of base 10, while ln is expressed in terms of base e. As an illustration, log of base 2 is denoted by log2 and log of base e by loge = ln (natural log).

The logarithm can be rewritten using the general rule. The common logarithm, which has a base of 10 always, is what you're dealing with when the log has no base.

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Answer:

I will helo you if you help mr

Step-by-step explanation:

Deal?

Answer: a>0.6

Step-by-step explanation:

If Lisa spends her income on veggie burgers and pints of soy milk and the price of veggie burgers is three times the price of a pint of soy milk, then when Lisa maximizes her utility she will buy both goods until the marginal utility of veggie burgers is three times the marginal utility of soy milk.

Therefore, if Lisa spends her income on veggie burgers and pints of soy milk and the price of veggie burgers is three times the price of a pint of soy milk, then when Lisa maximizes her utility she will buy both goods until the marginal utility of veggie burgers is three times the marginal utility of soy milk.

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Answer:

The irrational number is:

364−−√

(square root of 364)

The area of the shaded region is 82π - 68. Answer: 82π - 68

Given: The provided figure. We need to find the total area of the shaded region.

Step 1: Let us calculate the area of the triangle 8-10-18We have a= 8, b= 10, and c=18S = (a + b + c)/2 = (8+10+18)/2 = 18s = 18Area of triangle = sqrt(s(s-a)(s-b)(s-c))= sqrt(18*10*8*2) /4= 24

Step 2: Area of the shaded region

Area of sector OAB + Area of sector OCD + Area of Triangle ABC + Area of Triangle ADC - Area of Quadrilateral BPCD and Area of Quadrilateral APQO(3/4 π r²) + (5/4 π r²) + 48 + 36 - 128 and 24(3/4 π 12²) + (5/4 π 12²) + 48 + 36 - 128 and 24 =  27π + 55π + 48 + 36 - 128 and 24= 82π - 68

The area of the shaded region is 82π - 68.

Answer: 82π - 68

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The volume of cube in cm is (4cm)

Volume of cube is =96 CM^2

Let's consider he as the edge of cube

Surface area of is =6

That is symbol cube as (e^2)

As per the given question the surface are of cube is given as 96 cm^2

As we know

96=6^2

e^2=96/6

e^=16

e=√16

e=4cm

The volume of cube in centimetre is 4cm

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The values of p, q, and r are p = 2, q = 5, and r = 3, respectively.

Given that the lowest common multiple (LCM) of A and B is 2250, and the prime factorization of A is A = 2 × p × q¹, and the prime factorization of B is B = 2 × p² × q², we can compare the prime factorizations to determine the values of p, q, and r.

From the prime factorization of 2250 (2 × 3² × 5³), we can observe the following:

The prime factor 2 appears in both A and B.

The prime factor 3 appears in A.

The prime factor 5 appears in A.

Comparing this with the prime factorizations of A and B, we can deduce the following:

The prime factor p appears in both A and B, as it is present in the common factors 2 × p.

The prime factor q appears in both A and B, as it is present in the common factors q¹ × q² = q³.

From the above analysis, we can conclude:

p = 2

q = 5

r = 3.

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