uhh solve the question? i hope i find some haikyuu stans out there✌️

Uhh Solve The Question? I Hope I Find Some Haikyuu Stans Out There

Answers

Answer 1

Answer and Step-by-step explanation:

\((\frac{1.25 - x}{1.25x} ) * 100\\\\\\(\frac{1.25}{1.25x} - \frac{x}{1.25x} ) * 100\\\\(\frac{1}{x} - \frac{1}{1.25} ) * 100\\\\\frac{100}{x} - 80\\\\\\\)

Decreased by 20%

Answer 2

Answer:

YESSSSSS I LOVE HAIKYUU (my favorite ppl in haikyuu are iwaizumi, akaashi, kuroo, oikawa, and kenma- also suna)

Step-by-step explanation:

also 20% is ur answer


Related Questions

6th grade mathematics

Answers

Answer:

and?

Step-by-step explanation:

Hurricanes are large storms that form over warm waters out in the ocean. hurricanes are associated with low-pressure regions in the atmosphere. how does the low pressure associated with a hurricane help them to grow big and powerful?

Answers

A hurricane is a big rotating storm system that develops over warm ocean waters and usually travels westward toward the American mainland.

An Atlantic Ocean hurricane or a northern Pacific Ocean hurricane is a tropical storm. In most years, hurricanes develop between June 1 and November 30. The Taino Indian word "hurakan," which means "god of wind," is where the word "hurricane" originates.

A hurricane is a big rotating storm system that develops over warm ocean waters and usually travels westward toward the American mainland. Depending on the maximum sustained wind speeds, hurricanes are either classed as tropical storms or hurricanes. Hurricanes have winds of 74 mph or more, whereas tropical storms have winds of 39 to 73 mph.

The hurricane's eye, which is a calm, clear region encircled by powerful winds, is the most hazardous component of the storm. The hurricane's eye, which can be up to 30 miles across, frequently experiences the storm's greatest rains and highest winds.

A hurricane's landfall can result in flooding from storm surges, strong winds, and heavy rains. The increase in sea level that happens as a cyclone nears land is known as a storm surge. Along with coastal locations, this increase in water level has the potential to inflict significant harm and flooding.

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is the equation y + 1 equals 8 (x + 6) in point-slope form?​

Answers

Answer:

Yes

Step-by-step explanation:

The equation is y-y1=m(x-x1)

Answer: Yes

Step-by-step explanation:

The formula for point-slope form is y-1₁=m(x-x₁). The given equation is y+1=8(x+6). That means the given point is (-6,-1), and the slope is 8.

2x^3y + 18xy - 10x^2y - 90y

Part A: rewrite the expression so that the GCF is factored completely

Part B: rewrite the expression completely factored. Show the steps of your work

___________________________

Part A: the area of a square is (9x^2 + 24x + 16) square units. Determine the length of each side of the square by factoring the area expression completely. Show your work.

Part B: the area of a rectangle is (16x^2 - 25y^2) square units. Determine the dimensions of the rectangle by factoring the area expression completely. Show your work.

___________________________

f(x) = 2x^2 - 5x + 3

Part A: what are the x-intercepts of the graph of f(x)? Show your work

Part B: is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answer and show your work.


Part C: what are the steps you would use to graph f(x)? Justify that you can use the answer in part A and part B to draw the graph.

Answers

The expression where the greatest common factor (GCF) is factored completely is \(2x^3y + 18xy - 10x^2y - 90y = 2y(x^3 + 9x - 5x^2 - 45)\)

The expression completely factored in is

\(2y(x^3 + 9x - 5x^2 - 45) = 2y[x(x^2 - 5) + 9(x^2 - 5)]\\= 2y(x - 5)(x^2 + 9)\)

Please refer below for the remaining answers.

We have,

Part A:

To rewrite the expression 2x³y + 18xy - 10x²y - 90y so that the greatest common factor (GCF) is factored completely, we can factor out the common terms.

GCF: 2y

\(2x^3y + 18xy - 10x^2y - 90y = 2y(x^3 + 9x - 5x^2 - 45)\)

Part B:

To completely factor the expression, we can further factor the quadratic term.

\(2y(x^3 + 9x - 5x^2 - 45) = 2y[x(x^2 - 5) + 9(x^2 - 5)]\\= 2y(x - 5)(x^2 + 9)\)

Now,

Part A:

To determine the length of each side of the square given the area expression (9x² + 24x + 16), we need to factor it completely.

The area expression (9x² + 24x + 16) can be factored as (3x + 4)(3x + 4) or (3x + 4)².

Therefore, the length of each side of the square is 3x + 4.

Part B:

To determine the dimensions of the rectangle given the area expression (16x² - 25y²), we need to factor it completely.

The area expression (16x² - 25y²) is a difference of squares and can be factored as (4x - 5y)(4x + 5y).

Therefore, the dimensions of the rectangle are (4x - 5y) and (4x + 5y).

Now,

f(x) = 2x² - 5x + 3

Part A:

To find the x-intercepts of the graph of f(x), we set f(x) equal to zero and solve for x.

2x² - 5x + 3 = 0

The quadratic equation can be factored as (2x - 1)(x - 3) = 0.

Setting each factor equal to zero:

2x - 1 = 0 --> x = 1/2

x - 3 = 0 --> x = 3

Therefore, the x-intercepts of the graph of f(x) are x = 1/2 and x = 3.

Part B:

To determine if the vertex of the graph of f(x) is maximum or minimum, we can examine the coefficient of the x^2 term.

The coefficient of the x² term in f(x) is positive (2x²), indicating that the parabola opens upward and the vertex is a minimum.

To find the coordinates of the vertex, we can use the formula x = -b / (2a), where a and b are the coefficients of the quadratic equation.

For f(x),

a = 2 and b = -5.

x = -(-5) / (2 x 2) = 5/4

To find the corresponding y-coordinate, we substitute this x-value back into the equation f(x):

f(5/4) = 25/8 - 25/4 + 3 = 25/8 - 50/8 + 24/8 = -1/8

Therefore, the vertex of the graph of f(x) is at the coordinates (5/4, -1/8), and it is a minimum point.

Part C:

To graph f(x), we can start by plotting the x-intercepts, which we found to be x = 1/2 and x = 3.

These points represent where the graph intersects the x-axis.

Next,

We can plot the vertex at (5/4, -1/8), which represents the minimum point of the graph.

Since the coefficient of the x² term is positive, the parabola opens upward.

We can use the vertex and the symmetry of the parabola to draw the rest of the graph.

The parabola will be symmetric with respect to the line x = 5/4.

We can also plot additional points by substituting other x-values into the equation f(x) = 2x² - 5x + 3.

By connecting the plotted points, we can draw the graph of f(x).

The steps to graph f(x) involve plotting the x-intercepts, the vertex, and additional points, and then connecting them to form the parabolic curve.

The answer in part A (x-intercepts) and part B (vertex) are crucial in determining these key points on the graph.

Thus,

The expression where the greatest common factor (GCF) is factored completely is \(2x^3y + 18xy - 10x^2y - 90y = 2y(x^3 + 9x - 5x^2 - 45)\)

The expression completely factored in is

\(2y(x^3 + 9x - 5x^2 - 45) = 2y[x(x^2 - 5) + 9(x^2 - 5)]\\= 2y(x - 5)(x^2 + 9)\)

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Negative air pressure created by an air pump makes a vacuum cleaner able to collect air and dirt into a bag or other container. Below are several readings from a pressure gauge. Write rational numbers to represent each of the readings, and then order the rational numbers from least to greatest.

Gauge Readings ( pounds per square inch )
25 psi pressure
13 psi vacuum
6.3 psi vacuum
7.8 psi vacuum
1.9 psi vacuum
2 psi pressure
7.8 psi pressure
Pressure readings ( pounds per inch) answers:

Answers

The ordered rational numbers representing the gauge readings from least to greatest are 19/10, 63/10, 78/10, 78/10, 13/1, 25/1, 2/1.

To represent the gauge readings as rational numbers, we can express them as fractions with a common denominator.

Given readings:

25 psi pressure

13 psi vacuum

6.3 psi vacuum

7.8 psi vacuum

1.9 psi vacuum

2 psi pressure

7.8 psi pressure

Expressed as rational numbers with a common denominator:

25 psi = 25/1

13 psi = 13/1

6.3 psi = 63/10

7.8 psi = 78/10

1.9 psi = 19/10

2 psi = 2/1

7.8 psi = 78/10

Now, let's order these rational numbers from least to greatest:

1.9 psi = 19/10

6.3 psi = 63/10

7.8 psi = 78/10

7.8 psi = 78/10

13 psi = 13/1

25 psi = 25/1

2 psi = 2/1

Ordered from least to greatest:

19/10, 63/10, 78/10, 78/10, 13/1, 25/1, 2/1

Therefore, the ordered rational numbers representing the gauge readings from least to greatest are 19/10, 63/10, 78/10, 78/10, 13/1, 25/1, 2/1.

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A bridge, PR, across a river is 400 m long. Gabe is launching a canoe at point Q.
He will paddle in a diagonal line across the river to point P. He plans to return along a route beside the bridge from P to R, and then along the shore from R back to Q. How far will this be altogether?

Answers

Therefore, the total distance Gabe will paddle is 2x + 400 meters. The exact value of x depends on the width of the river, which is not provided in the given information.

To find the total distance Gabe will paddle, we need to consider the distance he will travel from Q to P, then from P to R, and finally from R back to Q.

First, let's consider the distance from Q to P. Since Gabe will paddle in a diagonal line across the river, this distance can be calculated using the Pythagorean theorem.

The length of the bridge (PR) is given as 400 meters, which is the hypotenuse of a right triangle. The width of the river can be considered as the perpendicular side, and the distance Gabe will paddle from Q to P is the other side. Let's call this distance x.

Using the Pythagorean theorem, we have:

x^2 + (width of the river)^2 = PR^2

Since the width of the river is not given, we'll represent it as w. Therefore:

x^2 + w^2 = 400^2

Next, let's consider the distance from P to R. Gabe will paddle along a route beside the bridge, which means he will travel the length of the bridge (PR) again. So, the distance from P to R is also 400 meters.

Finally, Gabe will paddle back from R to Q along the shore. Since he will follow the shoreline, the distance he will paddle is equal to the distance from Q to P, which is x.

To find the total distance, we add up the distances:

Total distance = QP + PR + RQ

= x + 400 + x

= 2x + 400

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what is 80=-20b? plz help

Answers

Answer:

b=-4

Step-by-step explanation:

80=-20b

If you divide -20 from both sides, you get -4=b. That's the answer.

PLZ MARK BRAINLIEST!!!

Answer:

-4

Step-by-step explanation:

80= - 20b

divide both by -20

that gives us -4=b

so, b= -4

Have a great day

Drag the cards to create a number that matches these rules.
The number ends in the tenths place.
8 is the nearest one when rounding

Answers

The tenths place one

Can someone please help me with this ASAP? Due today!! I will give brainliest

Read the question. Order them from the most likely to occur to the least likely to occur

Can someone please help me with this ASAP? Due today!! I will give brainliest Read the question. Order

Answers

Ordering the probabilities from most likely to occur to least likely to occur:

P(football, then volleyball) = 1/49

P(volleyball, then volleyball) = 1/25

P(baseball, then football, then volleyball) = 3/1000

P(baseball, then football, then football) = 5/2944

How to calculate the probability

P(event) = (number of ways the event can occur) / (total number of possible outcomes)

P(volleyball, then volleyball) if the ball is replaced after the first selection:

The probability of selecting a volleyball on the first draw is:

P(volleyball on first draw) = 10/50 = 1/5

Since the ball is replaced after the first selection, the probability of selecting a volleyball on the second draw is also 1/5. Therefore:

P(volleyball, then volleyball) = P(volleyball on first draw) * P(volleyball on second draw) = 1/5 * 1/5 = 1/25

P(baseball, then football, then volleyball) if the balls are replaced after each selection:

The probability of selecting a baseball on the first draw is:

P(baseball on first draw) = 15/50 = 3/10

Since the ball is replaced after each selection, the probability of selecting a football and a volleyball on the second and third draw respectively is also 1/10. Therefore:

P(baseball, then football, then volleyball) = P(baseball on first draw) * P(football on second draw) * P(volleyball on third draw) = 3/10 * 1/10 * 1/10 = 3/1000

P(baseball, then football, then football) if the balls are not replaced after each selection:

The probability of selecting a baseball on the first draw is:

P(baseball on first draw) = 15/50 = 3/10

Since the ball is not replaced after the first selection, the probability of selecting a football on the second draw is:

P(football on second draw) = 5/49

Since the ball is not replaced after the second selection, the probability of selecting a football on the third draw is:

P(football on third draw) = 4/48

Therefore: P(baseball, then football, then football) = P(baseball on first draw) * P(football on second draw) * P(football on third draw) = 3/10 * 5/49 * 4/48 = 5/2944

P(football, then volleyball) if the ball is not replaced after the first selection:

The probability of selecting a football on the first draw is:

P(football on first draw) = 5/50 = 1/10

Since the ball is not replaced after the first selection, the probability of selecting a volleyball on the second draw is:

P(volleyball on second draw) = 10/49

Therefore: P(football, then volleyball) = P(football on first draw) * P(volleyball on second draw) = 1/10 * 10/49 = 1/49

Ordering the probabilities from most likely to occur to least likely to occur:

P(football, then volleyball) = 1/49

P(volleyball, then volleyball) = 1/25

P(baseball, then football, then volleyball) = 3/1000

P(baseball, then football, then football) = 5/2944

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Use this image to find the measure of angles 1, 2, and 3.

Use this image to find the measure of angles 1, 2, and 3.

Answers

angle 2 = 103° (vertically opposite angles)
angle 1 = angle 3 = 77° (vertically opposite angles)

Answer:

∠ 1 = ∠ 3 = 63° , ∠ 2 = 117°

Step-by-step explanation:

∠ 2 and 117° are vertically opposite angles and are congruent , then

∠ 2 = 117°

∠ 1 and 117° are adjacent angles on a straight line and sum to 180°

∠ 1 + 117° = 180° ( subtract 117° from both sides )

∠ 1 = 63°

∠ 1 and ∠ 3 are vertically opposite angles and are congruent , then

∠ 3 = 63°

BRAINLIEST IF CORRECT

The weight of an object on the moon is 29its weight on Earth. Write 29 as a decimal.

29 in decimal form
Write out to 4 spaces after the decimal point, if possible and add the three dots if it repeats.​

Answers

Answer:

0.29        point twenty nine

Step-by-step explanation:

From the picture, we see that this boils down to finding the length of a side of a right triangle. The angle that we know about is 45^ and we know that the length of the side adjacent to the angle is 100 feet. We want to know about the length of the side that is opposite to the angle.
The tangent of an angle alpha is the ratio of the length of the opposite side to the length of the adjacent side

tan45^=x/100

1=x/100

x=100


So, the river is 100 feet across.
Now answer the following question(s).

1. Name the trigonometric ratios that was/were used to evaluate the width of the river?

2. List the most common units angles can be measured in.

Answers

Answer:

its should 2

Step-by-step explanation:

i need help with ratios of special triangles i was able to teach myself how to do the short leg and hyp but i cant figure out how to do the long leg on a 60 30 90

i need help with ratios of special triangles i was able to teach myself how to do the short leg and hyp

Answers

the hypotenuse is equal to twice the length of the shorter leg, which is the side across from the 30 degree angle. the longer leg, which is across from the 60 degree angle, is equal to multiplying the shorter leg by the square root of 3. so quite basically, hypotenuse = short leg square root, long leg = short leg squared :3 ( ex: short leg is 2 , 2^2 = 4, 2^3= 6 )

180°
26°
X = ??????????

18026X = ??????????

Answers

*edit bc i can't delete it so at least i will fix it.

the correct answer?? :

64°

Answer: 64 degrees

Step by step explanation:
Add all angles to get 296 degrees

We know all angles around a point = 360 degrees so we do 360 - 296 = 64

Which of the following terms describe the relationship between the number of notes and each syllable of a text and which do not?
-syllabic
-melismatic
-neumatic

Answers

The terms syllabic, melismatic, and neumatic are all related to the number of notes in relation to each syllable of a text. Syllabic means that each syllable of the text is sung to one note.

This is the simplest type of setting for text to music. In contrast, melismatic means that each syllable of the text is sung to many notes, creating a more intricate and ornamental melody. Neumatic is somewhere in between syllabic and melismatic, where each syllable is sung to a few notes, but not as many as in a melismatic setting.

Syllabic, melismatic, and neumatic all describe the relationship between the number of notes and each syllable of a text.

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find teh exact value of sin 2x given that sec x = 3/2 and csc y = 3 and x and y are in quadrant 1

Answers

The exact value  of \(sin 2x\) is \(4√5/9.\)

Given that \(sec x = 3/2 and csc y = 3\)where x and y are in the 2x = 2 sin x quadrant, we need to find the exact value of sin 2x.

In the first quadrant, we have the following values of the trigonometric ratios:\(cos x = 2/3 and sin y = 3/5\)

Also, we know that sin \(2x = 2 sin x cos x.\)

Now, we need to find sin x.

Having sec x = 3/2, we can use the Pythagorean identity

\(^2x + 1 = sec^2xtan^2x + 1 = (3/2)^2tan^2x + 1 = 9/4tan^2x = 9/4 - 1 = 5/4tan x = ± √(5/4) = ± √5/2\)

As x is in the first quadrant, it lies between 0° and 90°.

Therefore, x cannot be negative.

Hence ,\(tan x = √5/2sin x = tan x cos x = √5/2 * 2/3 = √5/3\)

Now, we can find sin 2x by using the value of sin x and cos x derived above sin \(2x = 2 sin x cos xsin 2x = 2 (√5/3) (2/3)sin 2x = 4√5/9\)

Therefore, the exact value  of sin 2x is 4√5/9.

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Decorative pots for flowers in the shape of a regular four-sided prism with external dimensions a = 18 cm. h = 16 cm are made of concrete. The thickness of the walls is 3 cm. How many m³ of concrete is needed to make 80 of such pots, if 5% more concrete should be counted due to waste?​

Answers

The amount of concrete required to make 80 pots is 0.24192 cubic meters after adding 5% of the required concrete.

Given that:External dimensions of the prism, a = 18 cmHeight of the prism, h = 16 cm Thickness of the walls, t = 3 cmNumber of pots, n = 80Wastage is 5% of the required concreteLet the side of the inner square be 'a1'. Then,a = a1 + 2t⇒ a1 = a - 2t = 18 - 2×3 = 12 cmVolume of the pot = volume of the outer prism - volume of the inner prismVolume of the outer prismVolume of the outer prism = a²hVolume of the outer prism = 18²×16 = 5184 cm³Volume of the inner prismVolume of the inner prism = a1²hVolume of the inner prism = 12²×16 = 2304 cm³Volume of the potVolume of the pot = 5184 - 2304 = 2880 cm³In m³, Volume of the pot = 2880/1000000 m³Volume of 80 such potsVolume of 80 pots = 80 × 2880/1000000 m³= 0.2304 m³Concrete required for the potsConcrete required = volume of 80 pots × (100 + 5)/100Concrete required = 0.2304 × 105/100 m³Concrete required = 0.24192 m³

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Show that \( \vec{F}=\left(2 x y+z^{3}\right) i+x^{2} j+3 x z^{2} k \) is conservative, find its scalar potential and work done in moving an object in this field from \( (1,-2,1) \) to \( (3,1,4) \) S

Answers

A vector field is conservative if its curl is zero. The curl of the vector field F is zero, so F is conservative. The scalar potential of F is given by: f(x, y, z) = x^3 + 2xyz + z^4/4 + C. The work done in moving an object in this field from (1, -2, 1) to (3, 1, 4) is: W = f(3, 1, 4) - f(1, -2, 1) = 70

A vector field is conservative if its curl is zero. The curl of a vector field is a vector that describes how the vector field rotates. If the curl of a vector field is zero, then the vector field does not rotate, and it is said to be conservative.

The curl of the vector field F is given by: curl(F) = (3z^2 - 2y)i + (2x - 3z)j

The curl of F is zero, so F is conservative.

The scalar potential of a conservative vector field is a scalar function that has the property that its gradient is equal to the vector field. In other words, F = ∇f.

The scalar potential of F is given by:

f(x, y, z) = x^3 + 2xyz + z^4/4 + C

The work done in moving an object in a conservative field from one point to another is equal to the change in the scalar potential between the two points. In this case, the work done in moving an object from (1, -2, 1) to (3, 1, 4) is:

W = f(3, 1, 4) - f(1, -2, 1) = 70

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The radius of a circle is increasing at a rate of 8 centimeters per minute. Find the rate of change of the area when the radius is 2 centimeters. Round your answer to one decimal place.

Answers

The rate of change of the area when the radius is 2 centimeters is approximately 100.5 square centimeters per minute.

To find the rate of change of the area of a circle when the radius is 2 centimeters, we need to use the formula for the area of a circle, which is \(A = πr^2.\)

We know that the radius is increasing at a rate of 8 centimeters per minute, so we can use this information to find the rate of change of the area.

We can start by finding the area of the circle when the radius is 2 centimeters. Substituting r = 2 into the formula, we get:

A = π(2)^2
A = 4π

So the area of the circle is 4π square centimeters when the radius is 2 centimeters.

Now, let's find the derivative of the area with respect to time. Using the power rule of differentiation, we get:

dA/dt = 2πr (dr/dt)

Substituting r = 2 and dr/dt = 8, we get:

dA/dt = 2π(2)(8)
dA/dt = 32π

So the rate of change of the area when the radius is 2 centimeters is 32π square centimeters per minute. To round this to one decimal place, we can use a calculator to get:

dA/dt ≈ 100.5

Therefore, the rate of change of the area when the radius is 2 centimeters is approximately 100.5 square centimeters per minute.

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The accounts payable clerk writes 5 checks every 50 minutes. How many checks will he use in 170 minutes?

Answers

Answer:

17

Step-by-step explanation:

5/50= x/170 multiply 5x170 divide that answer by 50. or bc u know that 5x10 = 50 u could divide 170 by 10 and still get 17

Answer:

17

Step-by-step explanation:

 17 because they write five checks each  50 minutes so it means that every 10 minutes on the check is created incel I went  50 +50+50 =150 And you can't add another 50 so than in 20 minutes to checks can be made and then so I made the conclusion that there can be 17 checks made

hope this helps :)

Two lifeguard towers are 546 yards apart, with tower B directly east of tower A. Both towers spot a hazard in the ocean. The bearing of the hazard from tower A is N35ºE, and the bearing of the hazard from tower B is N49ºW. Which formula gives the distance of the hazard from tower B?
A. \(a=546\frac{sin84^{\circ}}{sin55^{\circ}}\)
B. \(a=546\frac{sin49^{\circ}}{sin96^{\circ}}\)
C. \(a=546\frac{sin35^{\circ}}{sin96^{\circ}}\)
D. \(a=546\frac{sin55^{\circ}}{sin84^{\circ}}\)

Answers

Using the law of sines, the formula that gives the distance of the hazard from tower B is:

C. a = 546sin(35º)/sin(96º).

What is the law of sines?

Suppose we have a triangle in which:

The length of the side opposite to angle A is a.The length of the side opposite to angle B is b.The length of the side opposite to angle C is c.

The lengths and the sine of the angles are related as follows:

\(\frac{\sin{A}}{a} = \frac{\sin{B}}{b} = \frac{\sin{C}}{c}\)

From the situation described, we have that:

The angles are of 35º, 49º and 180 - (35 + 49) = 96º.The side opposite to the angle of 96º is of 546 yards.The angle opposite to the distance of the hazard to tower B is of 35º.

Hence the relation is:

sin(96º)/546 = sin(35º)/a

a = 546sin(35º)/sin(96º).

Which means that option C is correct.

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used to be that Jane could only run 4 laps round the track. She's been practicing and an now run 6 laps. By what percent did the number of laps she can run increase? Solve. (6-4)/(4)=([?])/(4) 2 10

Answers

The number of laps increases by 50 percent.

The number of laps Jane can run has increased by 50%. To find this, we can use the formula:

Percentage Increase = (New Value - Old Value) / (Old Value) × 100

In this case, the new value is 6 (the number of laps Jane can now run) and the old value is 4 (the number of laps Jane used to be able to run). Plugging these values into the formula gives us:

Percentage Increase = (6 - 4) / (4) × 100
Percentage Increase = 2 / 4 × 100
Percentage Increase = 0.5 × 100
Percentage Increase = 50%

Therefore, the number of laps Jane can run has increased by 50%.

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There are 1,620 minutes of music to be put on 9 CD's. If the same number of minutes fits on each CD, how many minutes of music fit on each CD?

Answers

Answer:

180 minutes

Step-by-step explanation:

take 1,620 divide it by 9 and there is your answer

hope this helped

Answe: 180 minutes

Step-by-step explanation                

you divide 1,620 divide it by 9 and there is your answer    

Solve the simultaneous equations
x + 5y = 20
x + 3y = 14

X= ?
Y= ?

Answers

Answer:

x=5, y=3

Explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Step-by-step explanation:

x=5 y=3 that is it that guy was right

(c) A non-uniform but spherically symmetric charge distribution has a charge density: rho(r)=rho 0

(1−r/R)
rho(r)=0

for r≤R
for r>R

where rho 0

=3Q/πR 3
is a positive constant. Show that the total charge contained in this charge distribution is Q. [4] Show that the electric field in the region r>R is identical to that created by a point charge Q at r=0 [2] Derive an expression for the electric field in the region r≤R. [5]

Answers

To show that the total charge contained in the charge distribution is Q, we integrate the charge density over the entire volume. The charge density is given by:

ρ(r) = ρ₀(1 - r/R) for r ≤ R,

ρ(r) = 0 for r > R,

where ρ₀ = 3Q/πR³.

To find the total charge, we integrate ρ(r) over the volume:

Q = ∫ρ(r) dV,

where dV represents the volume element.

Since the charge density is spherically symmetric, we can express dV as dV = 4πr² dr, where r is the radial distance.

The integral becomes:

Q = ∫₀ᴿ ρ₀(1 - r/R) * 4πr² dr.

Evaluating this integral gives:

Q = ρ₀ * 4π * [r³/3 - r⁴/(4R)] from 0 to R.

Simplifying further, we get:

Q = ρ₀ * 4π * [(R³/3) - (R⁴/4R)].

Simplifying the expression inside the parentheses:

Q = ρ₀ * 4π * [(4R³/12) - (R³/4)].

Simplifying once more:

Q = ρ₀ * π * (R³ - R³/3),

Q = ρ₀ * π * (2R³/3),

Q = (3Q/πR³) * π * (2R³/3),

Q = 2Q.

Therefore, the total charge contained in the charge distribution is Q.

To show that the electric field in the region r > R is identical to that created by a point charge Q at r = 0, we can use Gauss's law. Since the charge distribution is spherically symmetric, the electric field outside the distribution can be obtained by considering a Gaussian surface of radius r > R.

By Gauss's law, the electric field through a closed surface is given by:

∮E · dA = (1/ε₀) * Qenc,

where ε₀ is the permittivity of free space, Qenc is the enclosed charge, and the integral is taken over the closed surface.

Since the charge distribution is spherically symmetric, the enclosed charge within the Gaussian surface of radius r is Qenc = Q.

For the Gaussian surface outside the distribution, the electric field is radially directed, and its magnitude is constant on the surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q,

Simplifying:

E = Q / (4πε₀r²).

This is the same expression as the electric field created by a point charge Q at the origin (r = 0).

To derive an expression for the electric field in the region r ≤ R, we can again use Gauss's law. This time we consider a Gaussian surface inside the charge distribution, such that the entire charge Q is enclosed.

The enclosed charge within the Gaussian surface of radius r ≤ R is Qenc = Q.

By Gauss's law, we have:

∮E · dA = (1/ε₀) * Qenc.

Since the charge distribution is spherically symmetric, the electric field is radially directed, and its magnitude is constant on the Gaussian surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q.

Simplifying:

E = Q / (4πε₀r²).

This expression represents the electric field inside the charge distribution for r ≤ R.

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What are the conditions for using the t-distribution for inference on a population mean with a small sample

Answers

When conducting inference on a population mean using a small sample (n < 30), several conditions must be met to use the t-distribution.

First, the sample should be selected randomly from the population to ensure its representativeness.

Second, the population from which the sample is drawn should be approximately normally distributed, although this assumption becomes less critical with larger sample sizes due to the Central Limit Theorem. Checking for normality is important for small samples, either visually or through normality tests.

Third, the observations in the sample should be independent of each other, meaning they should not be related or influenced by one another.

Lastly, the sample should not contain extreme outliers that could significantly affect the sample mean and violate the assumptions of the t-distribution.

Meeting these conditions allows for the use of the t-distribution in calculating confidence intervals and conducting hypothesis tests for the population mean with small samples.

As the sample size increases (n ≥ 30), the t-distribution approaches the standard normal distribution, making the use of the t-distribution less necessary in those cases.

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FIND THE VALUE OF X AND W my answer is incorrect
PLEASE HELP ME
geometry

FIND THE VALUE OF X AND W my answer is incorrect PLEASE HELP MEgeometry

Answers

Step (1)

\((6w - 7) + (3x + 8) = 142\)

\(6w + 3x - 7 + 8 = 142\)

\(6w + 3x + 1 = 142\)

Subtract sides -1

\(6w + 3x + 1 - 1 = 142 - 1\)

\(6w + 3x = 141\)

Divided sides by 3

\( \frac{6}{3}w + \frac{3}{3}x = \frac{141}{3} \\ \)

\(2w + x = 47\)

I call above equation (( Ω ))

_________________________________

Step (2)

\(180 - 142 = 38\)

We have :

\((6w - 7) + 38 = (10w - 9)\)

\(6w - 7 + 38 = 10w - 9\)

\(6w + 31 = 10w - 9\)

Subtract sides -6w

\(6w - 6w + 31 = 10w - 6w - 9 \\ \)

\(31 = 4w - 9\)

Plus sides 9

\(31 + 9 = 4w - 9 + 9\)

\(40 = 4w\)

Divided sides by 4

\( \frac{40}{4} = \frac{4}{4}w \\ \)

\(w = 10\)

_________________________________

Do u remember (( Ω )) ?

Of course u do...

\(2w + x = 47\)

\(2(10) + x = 47\)

\(20 + x = 47\)

Subtract sides -20

\(20 - 20 + x = 47 - 20\)

\(x = 47 - 20\)

\(x = 27\)

_________________________________

And we're done.....♥️♥️♥️♥️♥️

Find the mean. 19, 11, 80, 19, 27, 19, 10, 25, 15

Answers

Steps - Add all of them up together and divide them by how many numbers there are , in this question there is 9 numbers.
Add the numbers up which give you 225.

So , 225 divided by 9 = 25.

Point C is on line segment BD. Given BC=x+4,BC=x+4, CD=5x,CD=5x, and BD=5x+7,BD=5x+7, determine the numerical length of line CD.

Answers

The numerical length of line CD is 15

Solving linear equations

From the question, we are to determine the numerical length of line CD

From the given information,

Point C is on line segment BD

Thus, we can write that

BC + CD = BD

Also, from the given information

BC = x+4

CD = 5x

BD = 5x +7

Therefore,

x+4 + 5x = 5x + 7

6x + 4 = 5x + 7

Collect like terms

6x - 5x = 7 - 4

x = 3

Now, substitute the value of x into the equation for line CD

CD = 5x

CD = 5×3

CD = 15

Hence, the numerical length of line CD is 15

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There are 1,920 fence posts used in a 12-kilometer stretch of fence. How may fence posts are used in 1 kilometer?​

Answers

Answer:

160

Step-by-step explanation:

Number of fence posts used in 1 kilometer

\( = \frac{1920}{12} \\ \\ = 160\)

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