Value of the expression 6x-2y 5y when x=10 and y=3.

The given statement is False. A test statistic based on point estimation is not used to construct the decision rule which defines the rejection region.

In hypothesis testing, a test statistic is calculated using sample data and a specific hypothesis to assess the strength of evidence against the null hypothesis. The decision rule, which determines whether to reject or fail to reject the null hypothesis, is based on the test statistic's distribution under the null hypothesis, rather than the point estimate itself.

The construction of the decision rule involves selecting a significance level (alpha), which represents the probability of rejecting the null hypothesis when it is actually true. The rejection region is determined based on the chosen significance level and the distribution of the test statistic. If the calculated test statistic falls within the rejection region, the null hypothesis is rejected; otherwise, it is not rejected.

Point estimation, on the other hand, is used to estimate an unknown parameter of interest, such as the population mean or proportion, based on sample data. It involves calculating a single value (point estimate) that represents the best guess for the parameter value. The point estimate is not directly involved in constructing the decision rule or defining the rejection region in hypothesis testing.

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False. A test statistic based on point estimation is not used to construct the decision rule that defines the rejection region.

The process of hypothesis testing involves constructing a decision rule to determine whether to accept or reject a null hypothesis based on sample data. The decision rule is typically defined using a critical region or rejection region, which is a range of values for the test statistic.

Point estimation, on the other hand, is a method used to estimate an unknown population parameter based on sample data. It involves calculating a single value (point estimate) that serves as an estimate of the population parameter.

While point estimation and hypothesis testing are both important concepts in statistics, they serve different purposes. Point estimation is used to estimate population parameters, whereas hypothesis testing involves making decisions based on sample data.

The decision rule for hypothesis testing is typically constructed based on the significance level (alpha) and the distribution of the test statistic, such as the t-distribution or the standard normal distribution. The test statistic is calculated using sample data and compared to critical values or calculated p-values to determine whether to reject the null hypothesis.

Therefore, the statement that a test statistic based on point estimation is used to construct the decision rule defining the rejection region is false.

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This is an equation.

See attachment for math work and answer.

Step-by-step explanation:

12x + 9x - 3 = 3(2x + 14)

12x + 9x - 3 = 6x + 42

21x - 3 = 6x + 42

21x - 6x = 42 + 3

15x = 45

15x/15 = 45/15

x = 3

Out of the given options, (a) and (d) are examples of time series while (b) and (c) are not.

A time series is a set of data points collected at regular intervals of time, with the aim of analyzing trends, patterns, and changes over time. In other words, it's a sequence of data points recorded at successive intervals of time. Here's a detailed explanation of each option:

a) The number of daily visitors to Niagara Falls during the month of April: This is an example of a time series. It shows the number of visitors to Niagara Falls every day in the month of April. The data points are collected at regular intervals of time (daily) and can be used to analyze patterns, trends, and changes in the number of visitors over time.

b) The recorded exam scores of students in a class: This is not an example of a time series. The data points represent a one-time measurement of exam scores and do not change over time.

c) The sales prices of single-family homes sold last month in Florida: This is not an example of a time series. The data points represent a one-time measurement of sales prices and do not change over time.

d) The current average prices of regular gasoline in different states of the U.S.: This is an example of a time series. The data points represent the current average prices of regular gasoline in different states of the U.S. The data points are collected at regular intervals of time and can be used to analyze patterns, trends, and changes in gasoline prices over time.

Therefore, Out of the given options, (a) and (d) are examples of time series while (b) and (c) are not.

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Answer:

3x+5

Step-by-step explanation:

Since you can't add 5 with x or 2x, the only way you can simplify is by adding the x and 2x together. x is basically 1x, so you get 3x.

Answer:

-150x

Step-by-step explanation:

(1) The length of side BC is 9 cm.

(2) The length of side PQ is 5.385 m.

(3) The length of side UW is 6.71 mm.

(4) The length of side XZ is 14.32 mm.

(5) The length of side EF is  6 cm.

The missing lengths of the right triangle is calculated by applying the Pythagoras theorem formula.

(1) The length of side BC is calculated as;

BC = √ (15² - 12² )

BC = 9 cm

(2) The length of side PQ is calculated as;

PQ = √ (5² + 2² )

PQ = 5.385 m

(3) The length of side UW is calculated as;

UW = √ (9² - 6² )

UW = 6.71 mm

(4) The length of side XZ is calculated as;

XZ = √ (14² + 3² )

XZ = 14.32 mm

(5) The length of side EF is calculated as;

EF = √ (10² - 8² )

EF = 6 cm

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Answer:

5 years

Step-by-step explanation:

by year five they both had the same amount

400-35=365

do that 5 times

225

100+25=125

do that 5 times

225

The solution is: Garret placed the treasure at the right place.

Here, we have,

The Cartesian plane can be used to locate the position of any given point with a coordinate. It consists of two numbered lines perpendicular to each other and intersecting at point zero of the lines.

From the statements given, 5 units from x-axis is not the same as 5 units on x-axis. Also, 3 units from y-axis is not the same as 3 units on y-axis.

So, distance 5 units from x-axis implies that a point 5 units after the x-axis. And also, distance 3 units from y-axis means 3 units after the y-axis.

With these conditions of the coordinate of the treasure, Garrett placed the treasure at the right place.

Hence, The solution is: Garret placed the treasure at the right place.

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complete question:

Garrett and Jeffrey are planning a treasure hunt. They decide to place a treasure at a point that is a

distance of 5 units from the x-axis and 3 units from the y-axis. Jeffrey places a treasure at point J, and

Garrett places one at point G. Who put the treasure in the right place? Explain how you know.

Answer:

divide both sides by -9.

because of the negative sign of this multiplication factor the inequality changes from "greater than" to "less than".

x < -3

that is the solution to this inequality.

Answer:

\(m= 20b-45\)

Step-by-step explanation:

Given data

The difference between the amount she sells each birdhouse for and the cost of supplies to build each birdhouse is $20

This means that her profit = $20

the number of birdhouses = b

cost of tools= $45

Hence the amount she earns from selling b houses is given as

\(m= 20b-45\)

Answer:

Total fee= 15m+2n

Step-by-step explanation:

If a storage tank holds 50,000 gallons of water then its volume is 189.25 cubic meters.

The volume of the storage tank in cubic meters can be calculated by first converting the volume from gallons to liters and then converting from liters to cubic meters.

Step 1: Convert the volume from gallons to liters:
50,000 gallons * 3.785 liters/gallon = 189,250 liters

Step 2: Convert the volume from liters to cubic meters:
189,250 liters * (1 cubic meter/1000 liters) = 189.25 cubic meters

Therefore, the volume of the storage tank is 189.25 cubic meters.

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Answer:

75 miles

Step-by-step explanation:

Please mark brainliest.

Answer:

There is 120 kilometers in 75 miles.

Step-by-step explanation:

1 mile = 1.609 kilometers.

In a class of 50 students, there are 365! / 315! ways that no two students will have the same birth date.

The total number of outcomes of two or more independent events equals the product of the number of outcomes of each individual event, according to this concept. A youngster, for example, who chooses six flavors of ice cream and three types of cones will have 6 x 3 = 18 distinct icecream options. According to the fundamental counting principle, if there are p ways to do one thing and q ways to do another, then there are pq ways to accomplish both.

Here,

There are 365 ways to choose the first student's birth date, 364 ways to choose the second student's birth date (since it can't be the same as the first student's), and so on, down to 316 ways to choose the 50th student's birth date (since it can't be the same as any of the first 49 students' birth dates).

So, the number of ways to choose the birth dates of 50 students so that no two are the same is,

= 365 × 364 × ... × 316

= 365! / (365 - 50)!

= 365! / 315!

There are 365! / 315! ways that no two students will have the same birth date in a class of size 50.

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Answer:

15 is your answer

Step-by-step explanation:

Answer:

15 is the answer

Step-by-step explanation:

ans 15

thanx

a. Jump with a bobbing motion: Shortest jump  b. Jump from deep knee flexion: Intermediate jump

c. Jump with fully extended knees: Longest jump ,In the long jump activity, three different jumping techniques were observed:

a) The bobbing motion involved bending and extending the knees and arms during the jump.

b) Starting from deep knee flexion meant initiating the jump from a position with knees bent and no motion prior to the jump.

c) Starting with fully extended knees involved jumping with the knees straight and no motion before the jump. During the performance, the lengths of each jump were measured. Trial results consistently indicated that the jump with the bobbing motion had the shortest length, while the jump starting from deep knee flexion had an intermediate length. The jump with fully extended knees consistently achieved the longest distance.

The observations reveal that starting the jump with fully extended knees and no knee motion results in the longest jump. The bobbing motion with knee and arm movements leads to the shortest jump. Deep knee flexion position falls between the two in terms of jump length.

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Answer:

Each gets 36 nights of sleep every 45 nights.

Step-by-step explanation:

This is called the handshake problem, which is the same problem as n guests (including host) attend a party.  At the end, everyone shakes hands with everyone else.  The number of handshakes is each person shakes hands with (n-1) other persons to give n(n-1) handshakes.  However, this counts each handshake twice (A with B and B with A), so the actual number of handshakes is n(n-1)/2

For n=10, then number of "teams" of two meerkats is 10(10-1)/2 = 45.  

So each meerkat gets to be on duty 9 nights out of 45, or gets 36 nights of sleep every 45 nights.

Answer:

The Career Tributes

5 miles from where she fell, in a pond.

A Cannon Boom

A sheet of plastic, a loaf of bread and an orange backpack containing numerous things that will help her survive.

The girl who made a fire underneath Katniss.

Step-by-step explanation:

I love the hunger games

Hope this helps :)

Answer:

50%

Step-by-step explanation:

8 - Pink

11 - Blue

4 - Yellow

7 - Purple

8+7  = 15

15/30

50% chance of grabbing a pink or purple

Answer:

b is the answer bro and try first then ask questions

Answer:

0.976 or 97.6%

Step-by-step explanation:

To calculate the frequency of the recessive allele, we need to use the information provided about the frequency of the dominant trait.

Let's assume that the particular dominant trait is determined by a single gene with two alleles: the dominant allele (A) and the recessive allele (a).

Given that 45 out of 1,000 babies are born with the dominant trait, we can infer that the remaining babies (1,000 - 45 = 955) do not have the dominant trait and can be considered as the recessive trait carriers.

The frequency of the recessive allele (q) can be calculated using the Hardy-Weinberg equation:

q = sqrt((Recessive individuals) / (Total individuals))

In this case, the total number of individuals is 1,000, and the number of recessive individuals is 955.

q = sqrt(955 / 1,000)

Using a calculator, we can find the value:

q ≈ 0.976

Therefore, the frequency of the recessive allele is approximately 0.976 or 97.6%.

The ordered pair of C'' after the sequence of transformation is (-14, -5)

Here we have know that  ABC can be plotted at A (-14, 14), B (-8, 11) & C (-14, 5).

Here we all know that the y-axis reflection rule is written as,

=> (x, y) → (-x, y)

And the value of x coordinate flips in sign from positive to negative, or vice versa. Then the value of y coordinate stays the same.

Then the point is look like C(-14,5) will then reflect based on the following rule,

=> (x, y) → (x, y)

The transformed coordinates are look like,

=> (-14,5) ((-14),5)

=> (-14,5)→ (14,5)

Therefore, here we have point C' located at (14,5) after applying the y-axis reflection rule on point C.

Now, the next operation to do is is the 180 degree rotation.

And this can be clockwise or counterclockwise.

Then the rotation rule is written as

=> (x, y) → (-x,y)

Now, for this time both coordinates flip in sign.

Here we have know that this rule only works if the center of rotation is the origin.

Now, let us apply that rotation rule to C' to find where C" is located.

Then the rule can be written as,  (x, y) → (-x,y)

=> (14,5)→ (-14, -5)

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Answer:

360 ft

Step-by-step explanation:

to find the total distance between the bases, you would multiply 90 by 4!

if it helps, since there are 4 bases, each of them being the same distance apart, they would make a square. each side of the square would be 90 ft. then find the perimeter! 90×4=360!

The probability value of (m, n) is (1, 2^1005).

Let n be a positive odd integer. We are asked to find the probability that its reciprocal gives a terminating decimal. This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.

If n is less than 2010, then its only possible prime factors are 3, 7, 11, ..., 2009, since all primes greater than 2009 are greater than n. We want n to have no prime factors other than 2 and 5. There are 1005 odd integers less than 2010.

We want to count how many of these have no odd prime factors other than 3, 7, 11, ..., 2009. This is equivalent to counting how many subsets there are of {3, 7, 11, ..., 2009}. There are 1004 primes greater than 2 and less than 2010. Each of these primes is either in a subset or not in a subset. Thus, there are 2^1004 subsets of {3, 7, 11, ..., 2009}, including the empty set.

Thus, the probability is:

P = (number of subsets with no odd primes other than 3, 7, 11, ..., 2009) / 2^1004

We can count this number using the inclusion-exclusion principle. Let S be the set of odd integers less than 2010. Let Pi be the set of odd integers in S that are divisible by the prime pi, where pi is a prime greater than 2 and less than 2010. Let Pi,j be the set of odd integers in S that are divisible by both pi and pj, where i < j.

Then, the number of odd integers in S that have no prime factors other than 2 and 5 is:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...|

where the union is taken over all sets of primes with at least one element and less than or equal to 1005 elements.

By the inclusion-exclusion principle:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...| = ∑ (-1)^k ⋅ (∑ |Pi1,i2,...,ik|)

where the outer summation is from k = 0 to 1005, and the inner summation is taken over all combinations of primes with k elements.

This simplifies to:

(1/2) ⋅ (2^1004 + (-1)^1005)

Thus, the probability is: P = (1/2^1004) ⋅ (1/2) ⋅ (2^1004 + (-1)^1005) = 1/2 + 1/2^1005. Hence, (m, n) = (1, 2^1005).

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Complete question:

If m/n is the probability that the reciprocal of a randomly selected positive odd integer less than 2010 gives a terminating decimal, with m and n being relatively prime positive integers. what is probability value of m and n?

The probability value of (m, n) is (1, 2^1005).This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.

Let n be a positive odd integer. We are asked to find the probability that its reciprocal gives a terminating decimal. This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.

If n is less than 2010, then its only possible prime factors are 3, 7, 11, ..., 2009, since all primes greater than 2009 are greater than n. We want n to have no prime factors other than 2 and 5. There are 1005 odd integers less than 2010.

We want to count how many of these have no odd prime factors other than 3, 7, 11, ..., 2009. This is equivalent to counting how many subsets there are of {3, 7, 11, ..., 2009}. There are 1004 primes greater than 2 and less than 2010. Each of these primes is either in a subset or not in a subset. Thus, there are 2^1004 subsets of {3, 7, 11, ..., 2009}, including the empty set.

Thus, the probability is:

P = (number of subsets with no odd primes other than 3, 7, 11, ..., 2009) / 2^1004

We can count this number using the inclusion-exclusion principle. Let S be the set of odd integers less than 2010. Let Pi be the set of odd integers in S that are divisible by the prime pi, where pi is a prime greater than 2 and less than 2010. Let Pi,j be the set of odd integers in S that are divisible by both pi and pj, where i < j.

Then, the number of odd integers in S that have no prime factors other than 2 and 5 is:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...|

where the union is taken over all sets of primes with at least one element and less than or equal to 1005 elements.

By the inclusion-exclusion principle:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...| = ∑ (-1)^k ⋅ (∑ |Pi1,i2,...,ik|)

where the outer summation is from k = 0 to 1005, and the inner summation is taken over all combinations of primes with k elements.

This simplifies to:

\((1/2) * (2^{1004} + (-1)^1005)\)

Thus, the probability is: P = \((1/2)^{1004}* (1/2) *(2^{1004} + (-1)^{1005}) = 1/2 + 1/2^{1005}.\)

Hence, (m, n) = (\(1, 2^{1005\)).

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\(\textit{internal division of a line segment using ratios} \\\\\\ A(-3,2)\qquad B(5,-4)\qquad \qquad \stackrel{\textit{ratio from A to B}}{2:6} \\\\\\ \cfrac{A\underline{P}}{\underline{P} B} = \cfrac{2}{6}\implies \cfrac{A}{B} = \cfrac{2}{6}\implies 6A=2B\implies 6(-3,2)=2(5,-4)\)

\((\stackrel{x}{-18}~~,~~ \stackrel{y}{12})=(\stackrel{x}{10}~~,~~ \stackrel{y}{-8}) \implies P=\underset{\textit{sum of the ratios}}{\left( \cfrac{\stackrel{\textit{sum of x's}}{-18 +10}}{2+6}~~,~~\cfrac{\stackrel{\textit{sum of y's}}{12 -8}}{2+6} \right)} \\\\\\ P=\left( \cfrac{ -8 }{ 8 }~~,~~\cfrac{ 4}{ 8 } \right)\implies P=\left(-1~~,~~\cfrac{1}{2} \right)\)

Answer:

x = -9/2

Step-by-step explanation:

1. Divide 9 by -1/3:

\(\frac{9}{1}\) ÷ \(-\frac{1}{3}\) = \(\frac{9}{1}\) · \(-\frac{3}{1}\)

= -27

2. Divide both sides by 2:

2(x - 9) = -27

\(\frac{2(x-9)}{2} = \frac{-27}{2}\)

(x - 9) = \(-\frac{27}{2}\)

3. Add 9 to both sides:

x = \(-\frac{9}{2}\)

(or 4.5 if you need it in decimal form)

hope this helps!

Answer:

3960

Step-by-step explanation:

1minute = 88rounds

45minutes = xrounds

1/45 = 88/x

45(88)= 3960

3960/1 = 3960

x = 3960

The gun fires 3960 rounds in 45 minutes.

A mathematical assessment of two numbers is called a proportion. If two sets of provided numbers rise or fall in the same relation, then the ratios are said to be directly proportional to each other.

Let x rounds would it fire in 45 minutes

As per the situation, we can write the proportion would be as:

1 minute : 88 rounds = 45minutes : x rounds

⇒ 1/88 = 45/x

Apply the cross-multiplication, and we get

⇒ x = 45(88)

⇒ x = 3960

This means a gun fires 3960 rounds in 45 minutes.

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The expression that equals to 9\(\sqrt[3]{10}\) is 5\(\sqrt[3]{10}\) + 4\(\sqrt[3]{10}\) so option 2 is correct.

Given expression:

Second option:

=  5\(\sqrt[3]{10}\) + 4\(\sqrt[3]{10}\)

Take cube root 10 as common

= \(\sqrt[3]{10}\)(5+4)

= ∛10(9)

= ∛10*9

= 9∛10.

which is equal to given expression.

Therefore the expression that equals to 9\(\sqrt[3]{10}\) is 5\(\sqrt[3]{10}\) + 4\(\sqrt[3]{10}\) so option 2 is correct.

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